Question

因此下面的代码提供了一个输入，根据过去的猜测，检查输入是否为一个字符长，并查看它是否为字母。否则，它应该返回该消息以重试。但是，在尝试代码时，我仅获得else条件，而无法获得if条件（应返回结果）。有谁知道为什么以及如何解决这个问题？

def get_guess(past_guesses):
"""
Checks if past_guesses is 1 letter, a letter or has been used before, and 
prompts user to try again

Example:
>>> get_guess(['A', 'a', 'c', 'd'])
'You need to enter one alphabetic character which you haven't\
already guessed. Try again'
>>> get_guess(['a', 'b', 'c', 'd'])
'a'

"""
answer = "'You need to enter one alphabetic character which you haven't\
already guessed. Try again'"

while True:
    guess = input("Guess a letter: ")
    if guess.isalpha() and len(guess) == 1 and guess not in past_guesses:
        past_guesses.append(guess)
        return guess
    else:
        print (answer)

Answer 1

Return不打印pass_guesses，它从函数中返回值，如果要使用它，则需要将其分配给变量。

a = get_guess(['A', 'a', 'c', 'd'])
print(a)

Answer 2

也许这就是您要寻找的。您的代码运行正常。您必须打印返回的结果。

print get_guess(['A', 'a', 'c', 'd'])

Answer 3

您如何打get_guess()？当您收到提示Guess a letter:时，如果您输入的字符不是一个字符，则您的代码将在else子句之后运行。

例如，如果在收到提示后键入abc，则abc不是一个字符，因此您将转到else子句并打印answer

如何检查输入以查看字符是否有字母，重复或超过一个字符长

3 个答案: