Question

我正在尝试从多个xsd文件生成一个Java类。但是我得到了这个错误。

org.xml.sax.SAXParseException; ...“ somelement”已经定义

我认为这是由于包含多次的通用类型造成的。

如何使用Maven生成Java类？

我在目录中具有以下架构：

xsd：

EXAMPLE_QualifyRS.xsd
EXAMPLE_QualifyRQ.xsd
EXAMPLE_Peble_CommonTypes.xsd
EXAMPLE_CommonTypes.xsd
EXAMPLE_SimpleTypes.xsd

EXAMPLE_QualifyRS.xsd

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.example.org/EXAMPLE/2007/00" elementFormDefault="qualified" version="1.002" id="EXAMPLE2016.1">
    <xs:include schemaLocation="EXAMPLE_CommonTypes.xsd"/>
    <xs:include schemaLocation="EXAMPLE_SimpleTypes.xsd"/>
    <xs:include schemaLocation="EXAMPLE_Peble_CommonTypes.xsd"/>
         <xs:element name="someelement">...</xs:element>

EXAMPLE_Peble_CommonTypes.xsd

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.example.org/EXAMPLE/2007/00" elementFormDefault="qualified" version="1.000" id="EXAMPLE2016.1">
    <xs:include schemaLocation="EXAMPLE_CommonTypes.xsd"/>

EXAMPLE_QualifyRQ.xsd

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.example.org/EXAMPLE/2007/00" elementFormDefault="qualified" version="1.001" id="EXAMPLE2016.1">
    <xs:include schemaLocation="EXAMPLE_CommonTypes.xsd"/>
    <xs:include schemaLocation="EXAMPLE_SimpleTypes.xsd"/>
    <xs:include schemaLocation="EXAMPLE_Peble_CommonTypes.xsd"/>
        <xs:element name="someelement">...</xs:element>

这是我如何在maven中生成类

<plugin>
                <groupId>org.codehaus.mojo</groupId>
                <artifactId>jaxb2-maven-plugin</artifactId>
                <version>2.4</version>
                <executions>
                    <execution>
                        <id>example-schema</id>
                        <phase>generate-sources</phase>
                        <goals>
                            <goal>xjc</goal>
                        </goals>
                        <configuration>
                            <xsdPathWithinArtifact>xsd</xsdPathWithinArtifact>
                            <addGeneratedAnnotation>true</addGeneratedAnnotation>
                            <laxSchemaValidation>true</laxSchemaValidation>
                            <laxSchemaValidation>true</laxSchemaValidation>
                            <readOnly>true</readOnly>
                            <verbose>true</verbose>
                            <sources>
                                <source>src/main/resources/xsd</source>
                            </sources>
                            <packageName>com.example</packageName>
                        </configuration>
                    </execution>
                </executions>
            </plugin>

Answer 1

假设您在common.xsd中有一个“人”，如下例：

<xs:schema xmlns="common.schema.def"
           xmlns:xs="http://www.w3.org/2001/XMLSchema"
           targetNamespace="common.schema.def"
           elementFormDefault="qualified">

    <xs:complexType name="Person">
        <xs:sequence>
                <xs:element name="name" type="xs:string"/>
                <xs:element name="age" type="xs:int"/>
        </xs:sequence>
    </xs:complexType>
</xs:schema>

您想在另一个架构中使用它。然后您会这样做：

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00"
           xmlns:xs="http://www.w3.org/2001/XMLSchema"
           xmlns:common="common.schema.def"
           targetNamespace="http://www.example.org/EXAMPLE/2007/00"
           elementFormDefault="qualified">
    <xs:import namespace="common.schema.def" schemaLocation="common.xsd"/>

    <xs:complexType name="someClass">
        <xs:sequence>
            <xs:element name="person" type="common:Person"/>
            <xs:element name="alias" type="xs:string"/>
        </xs:sequence>
    </xs:complexType>
</xs:schema>

编辑以回复评论：

发生名称冲突是因为您在插件中指定了程序包名称。然后，尝试将具有相同名称的类放在同一包下。让我们从插件中删除软件包的名称，并使用绑定为每个架构创建所需的软件包。

您的插件如下所示：

<plugin>
    <groupId>org.codehaus.mojo</groupId>
    <artifactId>jaxb2-maven-plugin</artifactId>
    <version>2.4</version>
    <executions>
        <execution>
            <id>example-schema</id>
            <phase>generate-sources</phase>
            <goals>
                <goal>xjc</goal>
            </goals>
            <configuration>
                <xsdPathWithinArtifact>xsd</xsdPathWithinArtifact>
                <addGeneratedAnnotation>true</addGeneratedAnnotation>
                <laxSchemaValidation>true</laxSchemaValidation>
                <laxSchemaValidation>true</laxSchemaValidation>
                <readOnly>true</readOnly>
                <verbose>true</verbose>
                <sources>
                    <source>src/main/resources/xsd</source>
                </sources>
                <xjbSources>
                    <xjbSource>src/main/resources/xjb</xjbSource>
                </xjbSources>
            </configuration>
        </execution>
    </executions>
</plugin>

bindings.xjb看起来像这样：

<jxb:bindings version="1.0"
              xmlns:jxb="http://java.sun.com/xml/ns/jaxb"
              xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <jxb:bindings schemaLocation="../xsd/common.xsd">
        <jxb:schemaBindings>
            <jxb:package name="common.packagename"/>
        </jxb:schemaBindings>
    </jxb:bindings>
    <jxb:bindings schemaLocation="../xsd/someothercommon.xsd">
        <jxb:schemaBindings>
            <jxb:package name="othercommon.packagename"/>
        </jxb:schemaBindings>
    </jxb:bindings>
</jxb:bindings>

要对其进行测试，我使用了另一个xsd，其元素名为Person，如下所示：

<xs:schema xmlns="othercommon.schema.def"
           xmlns:xs="http://www.w3.org/2001/XMLSchema"
           targetNamespace="othercommon.schema.def"
           elementFormDefault="qualified">

    <xs:complexType name="Person">
        <xs:sequence>
            <xs:element name="alias" type="xs:string"/>
            <xs:element name="id" type="xs:int"/>
        </xs:sequence>
    </xs:complexType>
</xs:schema>

同时使用两者的架构已更新为：

<xs:schema xmlns="http://www.example.org/EXAMPLE/2007/00"
           xmlns:xs="http://www.w3.org/2001/XMLSchema"
           xmlns:common="common.schema.def"
           xmlns:othercommon="othercommon.schema.def"
           targetNamespace="http://www.example.org/EXAMPLE/2007/00"
           elementFormDefault="qualified">
    <xs:import namespace="common.schema.def" schemaLocation="common.xsd"/>
    <xs:import namespace="othercommon.schema.def" schemaLocation="someothercommon.xsd"/>

    <xs:complexType name="someClass">
        <xs:sequence>
            <xs:element name="person" type="common:Person"/>
            <xs:element name="otherpersontype" type="othercommon:Person"/>
        </xs:sequence>
    </xs:complexType>
</xs:schema>

如何使用Maven从具有通用架构的多个XSD生成Java类

1 个答案: