Question

我在SQL Server中有一个这样的表（所有列都是数字）：

kubectl delete ns <name> --grace-period=0 --force

并且我希望将结果分布在另外2列中，例如这样（不带ID）：

Id1 | Id2 | Number | Qty
----+-----+--------+-------
  1 |  1  | 100001 | 100
  1 |  2  | 100002 | 110
  1 |  3  | 100003 | 120
  2 |  1  | 100004 | 130
  2 |  2  | 100005 | 200
  2 |  3  | 100006 | 300
  2 |  4  | 100007 | 400

有可能吗？谢谢。

Answer 1

您可以尝试以下操作：

SELECT CASE WHEN id2 = 1 THEN number ELSE '' END AS 'Number1',
CASE WHEN id2 = 1 THEN Qty ELSE '' END AS 'Qty1',
CASE WHEN id2 = 2 THEN number ELSE '' END AS 'Number2',
CASE WHEN id2 = 2 THEN Qty ELSE '' END AS 'Qty2',
CASE WHEN id2 = 3 THEN number ELSE '' END AS 'Number3',
CASE WHEN id2 = 3 THEN Qty ELSE '' END AS 'Qty3'
FROM tablename

Answer 2

唯一想到的是递归CTE。这将使您可以使用Id2中的n个值。您确定最后一行的Id2值正确吗，值为4？

Answer 3

您需要的是PIVOT。链接在这里： https://docs.microsoft.com/en-us/sql/t-sql/queries/from-using-pivot-and-unpivot?view=sql-server-2017

Answer 4

这有用吗？？

    DECLARE @T AS TABLE
        (
            id1 INT, 
            id2 int ,
            Number INT,
            Qty Int
        )
    Insert into @T
     SELECT 1,1,100001, 100 Union All
     SELECT 1,2,100002, 110 Union All
     SELECT 1,3,100003, 120 Union All
     SELECT 2,1,100004, 130 Union All
     SELECT 2,2,100005, 200 Union All
     SELECT 2,3,100006, 300 Union All
     SELECT 2,4,100007, 400 

    ;with cte1 as
        (
            select *,
            LEAD(Number) OVER(partition by id1 order by id2) as leadingNumber,
            LEAD(Qty) OVER(partition by id1 order by id2) as LeadingQty,

            ROW_NUMBER()over(partition by id1 order by (select null)) as rowNum
             from @T
        )
        ,
    cte2
        As
        (

            select 
            c1.id1,c1.Id2,
            c1.Number As Number1,c1.Qty as Qty1,c1.leadingNumber As Number2, c1.LeadingQty as Qty2
            ,LEAD(leadingNumber) OVER(partition by id1 order by id2)  as Number3,
            LEAD(LeadingQty) OVER(partition by id1 order by id2) as Qty3
            from cte1 c1
        )

    Select Number1,Qty1,Number2,Qty2,Number3,Qty3
    from cte2 where id2%3=1

Answer 5

好的。经过一些研究，我找到了一种生成动态列的解决方案，并使用PIVOT解决了我的问题。感谢所有提示。

DECLARE  @cols  AS NVARCHAR(MAX),  @query  AS NVARCHAR(MAX), @Param1 AS int

SET @cols = STUFF((SELECT  ',' + QUOTENAME(number) FROM View_GRTLinhasGRTLinhasTela WHERE id1 = @Param1 FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)') ,1,1,'')  

SET @query = 'SELECT *
FROM(
SELECT p.number, p.qty FROM View_GRTLinhasGRTLinhasTela p
WHERE p.id1 = @Param1) AS sourcetable
PIVOT (
SUM(qty) 
FOR number IN (' + @cols + ') ) AS pivottable'

EXEC sp_executesql @query

如何水平分布SQL结果？

5 个答案: