如何将这些多条件if语句转换为切换代码？

Question

我有以下JavaScript代码：

var myAge = parseInt ( prompt("Enter your age", 30), 10 );

if (myAge >= 0 && myAge <= 10) {
document.write("myAge is between 0 and 10 <br>");
}

if (!(myAge >= 0 && myAge <= 10)) {
document.write("myAge is NOT between 0 and 10<br>");
}

if (myAge >= 80 || myAge <= 10) {
document.write("myAge is 80 or above OR 10 or below<br>");
}

if ( (myAge >= 30 && myAge <= 39) || (myAge >= 80 && myAge <= 89) ) {
document.write("myAge is between 30 and 39 or myAge is " + "between 80 and 89");
}

我的任务是将其转换为switch语句。我试图这样做，但我想出了这段代码，但是当我在提示中输入数字时，文本不会显示：

var myAge = parseInt ( prompt("Enter your age", 30), 10 );

switch(myAge) {

case myAge >= 0 && myAge <= 10 :
document.write("myAge is between 0 and 10 <br>");
break;

case !(myAge >= 0 && myAge <= 10) : 
document.write("myAge is NOT between 0 and 10<br>");
break;

case myAge >= 80 || myAge <= 10 :
document.write("myAge is 80 or above OR 10 or below<br>");
break;

case  (myAge >= 30 && myAge <= 39) || (myAge >= 80 && myAge <= 89) : 
document.write("myAge is between 30 and 39 or myAge is " + "between 80 and 
89");
break;

}

这与我的休息时间有关吗？事情是？

Answer 1

开关并不是真的可以这样工作。

如果您想使用开关，可以使用switch（true）代替：

var myAge = parseInt ( prompt("Enter your age", 30), 10 );

switch(true) {


   *
   *
   *

}