x <- 10
Some code explanation, next code block hidden here but still evaluated
Some more code explanation
z <- x + y
The final output
# 10
Annex 1
=======
Each block individually:
x <- 10
y <- 10
z <- x + y
Annex 2
=======
If you want them more compactly concatenated:
x <- 10
y <- 10
z <- x + y
输出:
import numpy as np
mat = np.array([[1,21,3],[5,4,2],[56,12,4]])
mat_sort = mat[mat[:,2].argsort()]
print(mat_sort)
如果我希望基于任何列(例如3rd)进行反向排序,那么我对该代码进行哪些更改?意思是,我希望得到:
[[ 5 4 2]
[56 12 4]
[ 1 21 3]]
P.s是的,我知道这是一个简单的问题,但是我找不到我理解的答案,该答案基于矩阵而不是数组或向量。 TIA:)
答案 0 :(得分:1)
只需反转argsort
索引:
mat_sort = mat[mat[:, 2].argsort()[::-1]]
答案 1 :(得分:1)
print(mat_sort[::-1]) #just print in reverse