Question

我正在尝试查询一个用户具有多个续订但其中只有一个设置为“是”的查询。我想查询一个查询，如果所有查询都不为（0），则返回其名称。

SELECT u.id, CONCAT(u.fname, " ", u.lname) as full_name, renewals.renewRemind
     FROM user u 
INNER JOIN userRenewals renewals ON u.id = renewals.user_id
WHERE u.status = 1
AND renewals.renewRemind = 0
HAVING COUNT(renewals.renewRemind == 1) < 1

示例

Billy - Renewal
ID: 39 - YES
ID: 40 - NO
ID: 43 - NO
ID: 50 - NO

 Vicky - Renewal
    ID: 78 - NO
    ID: 80 - NO
    ID: 100 - NO
    ID: 119 - NO

Vicky应该出现在查询中，而不是Billy。

Answer 1

我会使用NOT EXISTS：

SELECT u.id, CONCAT(u.fname, " ", u.lname) AS full_name, r.renewRemind
FROM user u INNER JOIN 
     userRenewals r 
     ON u.id = r.user_id
WHERE NOT EXISTS (SELECT 1 FROM userRenewals r1 WHERE r1.user_id = r.user_id AND r1.renewRemind = 1);

Answer 2

听起来您正在寻找类似的事情：

SELECT u.id, CONCAT(u.fname, " ", u.lname) as full_name, renewals.renewRemind
     FROM user u 
INNER JOIN userRenewals renewals ON u.id = renewals.user_id
WHERE u.status = 1
AND renewals.renewRemind = 0
AND u.id not in (
    select user_id
    from renewals
    where renewRemind=1
)

Answer 3

这是我想出的：

SELECT u.id, CONCAT(u.fname, " ", u.lname) as full_name, renewals.renewRemind
     FROM user u 
 JOIN userRenewals renewals ON u.id = renewals.user_id
WHERE u.status = 1
group by u.id
having sum(renewals.renewremind) = 0

这里是fiddle

编辑1：

实际上，这可能会更快，因为它不需要连接：

SELECT distinct u.id, CONCAT(u.fname, " ", u.lname) as full_name FROM user u 
WHERE u.status = 1
and u.id not in (select user_id from userrenewals where renewremind=1);

Answer 4

需要简单的总和检查注意，我删除了续约条件为零的加入条件您希望所有案例都加入，而不是预先过滤1个案例，而只将总和设为零

SELECT
u.id,
CONCAT(u.fname, " ", u.lname) as full_name,
SUM (renewals.renewRemind) rsum
     FROM 
user u 
INNER JOIN userRenewals renewals ON u.id = renewals.user_id
WHERE
u.status = 1
HAVING rsum = 0

多个否定一个是SQL

4 个答案: