我有一个JSON,可以成功对它进行数字排序。
data["example"].sort(function (a, b) {
return a["one"] - b["two"];
});
// Output:
0: {location: "0"}
1: {location: "0"}
2: {location: "0"}
3: {location: "0"}
4: {location: "0"}
5: {location: "0"}
6: {location: "0"}
7: {location: "0"}
8: {location: "1"}
9: {location: "2"}
10: {location: "3"}
11: {location: "4"}
12: {location: "5"}
13: {location: "6"}
14: {location: "7"}
但是,我希望它从1
到∞
进行排序,然后再附加所有0
。
赞:
0: {location: "1"}
1: {location: "2"}
2: {location: "3"}
3: {location: "4"}
4: {location: "5"}
5: {location: "6"}
6: {location: "7"}
7: {location: "0"}
8: {location: "0"}
9: {location: "0"}
10: {location: "0"}
11: {location: "0"}
12: {location: "0"}
13: {location: "0"}
14: {location: "0"}
我敢肯定,对此有一个简单的解决方案,但是我找不到关于该特定数字排序的任何信息。
答案 0 :(得分:2)
您可以检查[latest_record_date]
是否为0,如果为0,请使用Infinity
进行排序以确保所有位置都将放置在数组的末尾。
datasource_id datasource_filter_column first_calculation_formula first_record_date previous_calculation_formula previous_record_date latest_calculation_formula latest_record_date
1234abc column1 CONCAT('first ','entry') 18-Oct-18 CONCAT('second ','entry') 20-Oct-18 CONCAT('third ','entry') 23-Oct-18
答案 1 :(得分:0)
获取输出后运行
for (let i = 0; i < array.length; i++) {
array[i].location = i+1;
}
或使用
之类的地图let counter = 1;
data["example"].sort(function (a, b) {
return a["one"] - b["two"];
}).map(c=> {c.location = counter++;return c});