无法从服务器中的网页导出Excel（XLSX）

Question

尝试将xlsx文件导出到本地可以正常工作，但是将其部署到服务器（使用unix命令）后无法正常工作。

当我打开excel时，出现错误，因为“由于扩展​​名无效，excel无法打开文件”

下面是导出xlsx的代码：

public String getXLSXWriter(ResultSet rs, String file_name)
{
    String filepath="";
    try {

        XSSFWorkbook workbook = new XSSFWorkbook();
        XSSFSheet sheet = workbook.createSheet(file_name);

        XSSFRow rowhead = sheet.createRow((int) 0);
         filepath=prop.getProperty("file_store_path")+file_name+timeStamp+".xlsx";

        FileOutputStream fileOut = new FileOutputStream(filepath);
        rowhead.createCell((int) 0).setCellValue("id");
        rowhead.createCell((int) 1).setCellValue("name");

        int i = 1;
        while (rs.next()){
            XSSFRow row = sheet.createRow((int) i);

            row.createCell((int) 0).setCellValue(rs.getString("id"));
            row.createCell((int) 1).setCellValue(rs.getString("domain_id"));
            row.createCell((int) 2).setCellValue(rs.getString("name") );

            i++;
        }

        workbook.write(fileOut);
        fileOut.close();
        System.out.println("XLSX done!!"); 
        } catch (SQLException e1) {
            e1.printStackTrace();
        } catch (FileNotFoundException e1) {
            e1.printStackTrace();
        } catch (IOException e1) {
            e1.printStackTrace();
        }
    return filepath;
}


public void getDownloaded(String filepath,HttpServletResponse response)
{
    try {
        File file=new File(filepath);
        response.setContentType("application/octet-stream");
        response.setHeader("Content-Disposition","attachment;filename="+file.getName());
        FileInputStream in=new FileInputStream(file);
        ServletOutputStream out=response.getOutputStream();
        byte[] outputByte = new byte[4096];
        //copy binary content to output stream
        int length;
        while((length=in.read(outputByte, 0, 4096)) != -1){
            out.write(outputByte, 0, length);
        }

        in.close();
        out.flush();
        out.close();
    } catch (Exception e) {
        e.printStackTrace();
    }
}