Question

我可以看到这段代码

DiskFileUpload fu = new DiskFileUpload();
        // If file size exceeds, a FileUploadException will be thrown
        fu.setSizeMax(1000000);

        List fileItems = fu.parseRequest(request);
        Iterator itr = fileItems.iterator();

        while(itr.hasNext()) {
          FileItem fi = (FileItem)itr.next();

          //Check if not form field so as to only handle the file inputs
          //else condition handles the submit button input
          if(!fi.isFormField()) {
            System.out.println("nNAME: "+fi.getName());
            System.out.println("SIZE: "+fi.getSize());
            //System.out.println(fi.getOutputStream().toString());
            File fNew= new File(application.getRealPath("/"), fi.getName());

            System.out.println(fNew.getAbsolutePath());
            fi.write(fNew);
          }
          else {
            System.out.println("Field ="+fi.getFieldName());
          }
        }

我想知道这段代码是什么：

List fileItems = fu.parseRequest(request);
            Iterator itr = fileItems.iterator();

...意味着HttpClient？我应该按部分上传文件还是什么意思？我想用我的桌面应用程序上传视频文件，但我不知道如何组织HttpClient。请帮我理解。

客户端

import org.apache.http.params.CoreProtocolPNames;
import org.apache.http.util.EntityUtils;


public class PostFile {
  public static void main(String[] args) throws Exception {
    HttpClient httpclient = new DefaultHttpClient();
    httpclient.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);

    HttpPost httppost = new HttpPost("http://localhost:8080/uploadtest");
    File file = new File("C:\\file.flv");

    MultipartEntity mpEntity = new MultipartEntity();
    ContentBody cbFile = new FileBody(file, "binary/octet-stream");
    mpEntity.addPart("userfile", cbFile);


    httppost.setEntity(mpEntity);
    System.out.println("executing request " + httppost.getRequestLine());
    HttpResponse response = httpclient.execute(httppost);
    HttpEntity resEntity = response.getEntity();

    System.out.println(response.getStatusLine());
    if (resEntity != null) {
      System.out.println(EntityUtils.toString(resEntity));
    }
    if (resEntity != null) {
      resEntity.consumeContent();
    }

    httpclient.getConnectionManager().shutdown();
  }
}

服务器

public void doPut(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    System.out.println("Content Type ="+request.getContentType());


    try {
      DiskFileUpload fu = new DiskFileUpload();
      // If file size exceeds, a FileUploadException will be thrown
      fu.setSizeMax(1000000);

      List fileItems = fu.parseRequest(request);
      Iterator itr = fileItems.iterator();

      while (itr.hasNext()) {
        FileItem fi = (FileItem) itr.next();

        //Check if not form field so as to only handle the file inputs
        //else condition handles the submit button input
        if (!fi.isFormField()) {
          System.out.println("nNAME: " + fi.getName());
          System.out.println("SIZE: " + fi.getSize());
          //System.out.println(fi.getOutputStream().toString());
          File fNew = new File("D:\\uploaded.flv");

          System.out.println(fNew.getAbsolutePath());
          fi.write(fNew);
        }
        else {
          System.out.println("Field =" + fi.getFieldName());
        }
      }
    }
    catch (Exception ex) {
    }


  }

我想上传文件＆gt; = 1Gb。我做错了什么？

Answer 1

不，您不必按部件上传文件。在表单中，您可以拥有“file”类型的多个输入字段。

List fileItems = fu.parseRequest(request);

上面的代码会返回您请求中所有“文件”输入字段的列表。因此，如果您有两个文件字段，则会得到两个FileItem及其内容。下一个声明：

Iterator itr = fileItems.iterator();

用于获取迭代器并迭代刚从请求中提取的FileItem列表。记住，每个FileItem对象都是您上传的文件。

FileUpload和HttpClient上传项目和部分

1 个答案: