Question

在“ Proc制表”输出中，类标题高于类级别。有没有办法将班级标题移动到班级旁边的自己的栏中？在图像的所需输出中，“教育”的班级标题位于其自己的单元格中，靠近班级。我该怎么做？

PROC FORMAT;
PICTURE PCTF (ROUND) OTHER='009.9%';
RUN;
ODS HTML PATH="%SYSFUNC(GETOPTION(WORK) )" STYLE=JOURNAL1A;
TITLE "Question 21x";
PROC TABULATE DATA = 208s;
CLASS EDUC 
      AREA
      AGE 
      SEX 
      CENRACE 
      POVERTY 
      EDUC 
      INSURE 
      HEALTH
      Q21x;
CLASSLEV EDUC AREA AGE SEX CENRACE POVERTY EDUC INSURE HEALTH Q21x ;

TABLE AREA    = 'Area in Region' * (ROWPCTN='   '*f=PCTF.)
      AGE     = 'Age'            * (ROWPCTN='   '*f=PCTF.) 
      SEX                        * (ROWPCTN='   '*f=PCTF.)
      CENRACE = 'Race'           * (ROWPCTN='   '*f=PCTF.)
      POVERTY = 'Poverty Status' * (ROWPCTN='   '*f=PCTF.)
      EDUC                       * (ROWPCTN='   '*f=PCTF.)
      INSURE                     * (ROWPCTN='   '*f=PCTF.) 
      HEALTH                     * (ROWPCTN='   '*f=PCTF.) , Q21x = '   ';
RUN;

Answer 1

您可以将现有数据转换为分类形式，这将使您更好地控制行维布局。将ROWPCTN移动到列维度中，以消除空白列（在行标题中），否则如果ROWPCTN在行维度中会出现空白列。使用NOCELLMERGE来防止在第一数据行中合并单元格。

例如，以

开头

data have;
  do personid = 1 to 1000;
    area = cats('area_',0 + floor(5 * ranuni(123)));
    age  = cats('age_',13 + floor(7 * ranuni(123)));
    sex  = cats('sex_',1 + floor( 2 * ranuni(123)));
    q21x = byte(65+(5*ranuni(123)));
    output;
  end;  
  label area = 'Area Label';
run;

proc tabulate data=have;
  class area age sex q21x;
  table 
    ( area age sex ) * (rowpctn=' '), q21x
  / nocellmerge;
run;

以及转置后的数据版本

proc transpose data=have out=have_for_table;
  by personid q21x notsorted;
  var area age sex;
run;

proc tabulate data=have_for_table missing;
  class _name_ _label_ col1 q21x;
  table 
    _name_='' * _label_='' * col1=''
    ,
    q21x * (rowpctn='')
    /
    nocellmerge
    ;
run;

将Proc制表类标题移到另一列

1 个答案: