Question

Postgresql有一个geom_id，它基本上是由地图上某个点的纬度和经度生成的id。如何使用该ID使用GSON创建JSON对象？

这是我的解析器。

package database;

import com.google.gson.Gson;
import com.google.gson.GsonBuilder;

import database.GeoJSONParser.Layer.Layer_Geometry;

import java.io.IOException;
import java.io.InputStreamReader;
import java.io.Reader;

public class GeoJSONParser {

    public class Layer {

        public class Layer_Geometry {
            private String type;
            private String coordinates;

            @Override
            public String toString() {
                return type + " - " + coordinates;
            }
        }

        public class Geom_return {
            private Layer_Geometry Geom ;

            @Override
            public String toString() {
                return (" + Geom + ");
            }
        }

        public class JSONtoJava {
            public void main(String[] args) throws IOException {
                Reader reader = new InputStreamReader(GeoJSONParser.class.getResourceAsStream("Server1.json"));
                Gson gson = new GsonBuilder().create();
                Geom_return Geom1 = gson.fromJson(reader, Geom_return.class);
                System.out.println(Geom1);
                reader.close();
            }
        }
    }
}

这是JSON：

{"type":"Feature", "id":"OpenLayers.Feature.Vector_108", 
"properties":{}, "geometry":{"type":"Point", "coordinates":[13.148438036442, 7.6347658038139]}, 
 "crs":{"type":"OGC", "properties":{"urn":"urn:ogc:def:crs:OGC:1.3:CRS84"}}}

如何使用将从postgresql表返回的geom对象构建JSON构建器？

如何使用从postgresql获得的geom id中使用GSON来构建JSON对象？

0 个答案: