如何跳过我的PHP脚本的某些部分? (使我的页面加载速度更快)

时间:2011-03-14 03:35:35

标签: php pagination

<?php
$rows_per_page = 2;
$cols_per_page = 2;
$image_href = '<a href=/';
$image_links = array('file1/page1>', 'file2/page2>', 'file3/page3>',  
'file4/page4>',   'file5/page5>', 'file6/page6>', 'file6/page6>',  
'file/page7>', 'file/page8>', 'subfile/page9>');
$img_srcs = '<img src="https://s3.amazonaws.com/imagetitle/';
$images = array();

for($i = 1; $i < 10; $i++)
{
    $images[$i] = $i;
}
$image_ending = '.png" height="200" width="200" /></a>';
$image_descriptions = array('<br />something', '<br />description', 
'<br />arbitrary', 'random', '<br />you', '<br />get', '<br />the',  
'<br />idea', '<br />itsdescriptions');  
$total_images = count($images);
$images_per_page = $rows_per_page * $cols_per_page;
$total_images = count($images);
$total_pages = ceil($total_images / $images_per_page);
$current_page = (int) $_GET['page'];
if($current_page<1 || $current_page>$total_pages)
{
    $current_page = 1;
}

//Get records for the current page
$page_image_links = array_splice($image_links, ($current_page-1)*$images_per_page, $images_per_page);
$page_images = array_splice($images, ($current_page-1)*$images_per_page, $images_per_page);
$page_image_descriptions = array_splice($image_descriptions, ($current_page-1)*$images_per_page, $images_per_page);
$slots = "<table border=\"1\">";
for($row=0; $row<$rows_per_page; $row++)
{
    $slots .= "<tr>";
    for($col=0; $col<$cols_per_page; $col++)
    {
        $imgIdx = ($row * $rows_per_page) + $col;
        $img = (isset($page_images[$imgIdx])) ? "{$image_href}{$page_image_links[$imgIdx]}{$img_srcs}{$page_images[$imgIdx]}{$image_ending}{$page_image_descriptions[$imgIdx]}" : '&nbsp;';
        $slots .= "<td>$img</td>";
    }
    $slots .= "</tr>";
}
$slots .= "</table>";

//Create pagination links
$first = "First";
$prev  = "Prev";
$next  = "Next";
$last  = "Last";
if($current_page>1)
{
    $prevPage = $current_page - 1;
    $first = "<a href=\"blah.php?page=1\">First</a>";
    $prev  = "<a href=\"blah.php?page={$prevPage}\">Prev</a>";
}
if($current_page<$total_pages)
{
    $nextPage = $current_page + 1;
    $next = "<a href=\"blah.php?page={$nextPage}\">Next</a>";
    $last = "<a href=\"blah.php?page={$total_pages}\">Last</a>";
}

?>
<html>
<title></title>
<body>
<h2>Here are the records for page <?php echo $current_page; ?></h2>
  <ul>
    <?php echo $slots; ?>
  </ul>
Page <?php echo $current_page; ?> of <?php echo $total_pages; ?>
<br />
<?php echo "{$first} | {$prev} | {$next} | {$last}"; ?>
</body>
</html>

所以基本上上面这段代码可以很容易地提供图像及其链接。目前,我没有那么多图像,因此页面运行速度非常快。但是,从长远来看,我在想。如果我说10,000张图片,则需要花费很长时间来处理每个分页页面,因为我会将file1 / page1的$ image_links提升到file10000 / page10000,以及10000个不同的图像描述!有没有办法阻止Web浏览器读取或跳过脚本的某些部分(在我的情况下为$ image_links和$ image_descriptions)?这样,它就不需要通读所有10000 $ image_links和$ image_descriptions。

谢谢!

1 个答案:

答案 0 :(得分:4)

在这种情况下,人们通常会将每张图像的记录存储在数据库中。这样,您不必每次都创建整个图像列表。因此,您只需检索用户当前正在查看的页面的图像。

缓存

您还可以缓存结果。有各种各样的方法,类和库可以做到这一点,但它基本上涉及做这样的事情:

$cache_key = 'cache-page-'.$pagenumer.'.cache';
if (!file_exists($cache_key)) {

    ob_start();
    // all your code comes here - to make it very
    // fast, you can do an include() here on the other file
    include 'the-rest-of-your-code-example.php';
    $output = ob_get_clean();
    $fp = fopen($cache_key, 'w');
    fwrite($fp, $output);
    fclose($fp);

} else {
    $output = file_get_contents($cache_key);
}

// And finally echo the content
echo $output;