Question

有人知道如何将包含没有参数名称的json的字符串转换为C＃数组。我的代码从RESTApi接收到json

[["name","surname","street","phone"],
["alex","smith","sky blue way","07747233279"],
["john","patterson","richmond street","07658995465"]]

我在这里看到的每个示例都涉及参数名称，它们的json看起来像这样

[Name:"alex",Surname:"smith",street:"sky blue way",phone:"07747233279"],
[Name:"john",Surname:"patterson",street:"richmond street",phone:"07658995465"]]

我正在尝试使用JavaScriptSerializer，但我不知道如何为此类JSON正确维护类

Answer 1

您可以执行此操作，这将为您提供字符串列表的列表

var input = "[[\"name\", \"surname\", \"street\", \"phone\"],\r\n\t[\"alex\", \"smith\", \"sky blue way\", \"07747233279\"],\r\n\t[\"john\", \"patterson\", \"richmond street\", \"07658995465\"]]";
var results = JsonConvert.DeserializeObject<List<List<string>>>(input);

foreach (var item in results)
    Console.WriteLine(string.Join(", ", item));

输出

name, surname, street, phone
alex, smith, sky blue way, 07747233279
john, patterson, richmond street, 07658995465

Full Demo Here

Answer 2

这并不是OP所要问的（二维数组），而是我对这个问题的解决方法。

似乎您有一群人，所以我要创建一个Person类，如下所示：

public class Person
{
    public string Name { get; set; }
    public string Surname { get; set; }
    public string Street { get; set; }
    public string Phone { get; set; }
}

然后是一个解析器类，它将json字符串作为参数，并返回Person的集合：

public class PersonParser
{
    public IEnumerable<Person> Parse(string content)
    {
        if (content == null)
        {
            throw new ArgumentNullException(nameof(content));
        }

        if (string.IsNullOrWhiteSpace(content))
        {
            yield break;
        }

        // skip 1st array, which contains the property names
        var values = JsonConvert.DeserializeObject<string[][]>(content).Skip(1);

        foreach (string[] properties in values)
        {
            if (properties.Length != 4)
            {
                // ignore line? thrown exception?
                // ...
                continue;
            }

            var person = new Person
            {
                Name = properties[0],
                Surname = properties[1],
                Street = properties[2],
                Phone = properties[3]
            };

            yield return person;
        }
    }
}

使用代码：

string weirdJson = @"[[""name"",""surname"",""street"",""phone""],
[""alex"",""smith"",""sky blue way"",""07747233279""],
[""john"",""patterson"",""richmond street"",""07658995465""]]";

var parser = new PersonParser();
IEnumerable<Person> people = parser.Parse(weirdJson);

foreach (Person person in people)
{
    Console.WriteLine($"{person.Name} {person.Surname}");
}

将json反序列化为2d数组

2 个答案: