这是我的剧本。我曾经尝试过,但无法获得正确的结果。请提供一些建议,谢谢和赞赏。
function groupBy() {
var list = [{
"id": "009",
"Nm": "Model 1",
"pid": "adidas"
},
{
"id": "007",
"Nm": "Model 1",
"pid": "adidas"
},
{
"id": "006",
"Nm": "Model 1",
"pid": "adidas"
},
{
"id": "pm1",
"Nm": "Model 1",
"pid": "puma"
},
{
"id": "003",
"Nm": "Model 1",
"pid": "adidas"
},
{
"id": "pm5",
"Nm": "Model 1",
"pid": "puma"
},
{
"id": "aj1",
"Nm": "Model 1",
"pid": "nike"
},
{
"id": "aj2",
"Nm": "Model 1",
"pid": "nike"
}
];
var output = [];
for (var i = 0; i < list.length; i++) {
if (list[i].pid != undefined) {
output.push(list[i]);
}
}
console.log(output);
}
groupBy();
答案 0 :(得分:5)
一种选择是将reduce
插入由pid
索引的对象,该对象的值为数组。在每次迭代中,如果不存在,请在适当的属性处创建数组,然后推送到该数组:
var list = [
{"id":"009","Nm":"Model 1","pid":"adidas"},
{"id":"007","Nm":"Model 1","pid":"adidas"},
{"id":"006","Nm":"Model 1","pid":"adidas"},
{"id":"pm1","Nm":"Model 1","pid":"puma"},
{"id":"003","Nm":"Model 1","pid":"adidas"},
{"id":"pm5","Nm":"Model 1","pid":"puma"},
{"id":"aj1","Nm":"Model 1","pid":"nike"},
{"id":"aj2","Nm":"Model 1","pid":"nike"}
];
console.log(
list.reduce((a, item) => {
const { pid } = item;
if (!a[pid]) a[pid] = [];
a[pid].push(item);
return a;
}, {})
);
答案 1 :(得分:1)
您在那里很近。但是[]
是要初始化数组而不是javascript中的对象。在JS中,它是{}
。
遵循是您可以完成此操作的众多方法之一。
function groupBy() {
var list = [
{"id":"009","Nm":"Model 1","pid":"adidas"},
{"id":"007","Nm":"Model 1","pid":"adidas"},
{"id":"006","Nm":"Model 1","pid":"adidas"},
{"id":"pm1","Nm":"Model 1","pid":"puma"},
{"id":"003","Nm":"Model 1","pid":"adidas"},
{"id":"pm5","Nm":"Model 1","pid":"puma"},
{"id":"aj1","Nm":"Model 1","pid":"nike"},
{"id":"aj2","Nm":"Model 1","pid":"nike"}
];
// Initialize output as an object
var output = {};
for (var i = 0; i < list.length; i++){
// 'objectKey' is where you group the list item by its 'pid'
var objectKey = list[i].pid;
// If there's a 'pid' in the list item, but 'output' is not an array yet, then..
if (objectKey && !output.hasOwnProperty(objectKey)){
// Initialize output.group to be an array
output[ objectKey ] = [];
}
// Then finally, store the list into output's group that we created above.
output[ objectKey ].push( list[i] );
}
console.log(output);
}
groupBy();
答案 2 :(得分:0)
将此方法用于您的任何组
const groupBy = function(arr, prop) {
return arr.reduce(function(groups, item) {
const val = item[prop]
groups[val] = groups[val] || []
groups[val].push(item)
return groups
}, {})
}
const list = [
{"id":"009","Nm":"Model 1","pid":"adidas"},
{"id":"007","Nm":"Model 1","pid":"adidas"},
{"id":"006","Nm":"Model 1","pid":"adidas"},
{"id":"pm1","Nm":"Model 1","pid":"puma"},
{"id":"003","Nm":"Model 1","pid":"adidas"},
{"id":"pm5","Nm":"Model 1","pid":"puma"},
{"id":"aj1","Nm":"Model 1","pid":"nike"},
{"id":"aj2","Nm":"Model 1","pid":"nike"}
];
const groupOutput = groupBy(list, 'pid');
您将密钥作为第二个参数传递给groupBy进行分组依据。