Question

当我尝试使用多个异常时，由于某种原因，我得到了错误：

SyntaxError: default 'except:' must be last

代码：

try:
    to_address = item["tx"]
    amount_xrp = int(item["tx"]["TakerGets"])/1000000.0
except:
    to_address = item["tx"]
except:
    to_address = "Cancellation"#item["tx"]["TakerPays"]
    amount_xrp = "NA"

Answer 1

except:子句捕获任何异常。两次使用没有意义。是什么意思？

Answer 2

您的示例不正确的Python语法。您可以执行以下操作：

try:
    to_address = item["tx"]
    amount_xrp = int(item["tx"]["TakerGets"])/1000000.0

except:
    try:
        to_address = item["tx"]

    except:
        to_address = "Cancellation"#item["tx"]["TakerPays"]
        amount_xrp = "NA"

Answer 3

对于您要达到的目标，我的最佳猜测是将to_address设置为Cancellation（如果不在items中），并设置amount_xrp如果to_address没有一个'TakerGets'键，则将其设置为“ NA”。

to_address = item.get('tx', 'Cancellation') #returns 'Cancellation' if no key 'tx'
amount_xrp = 'NA'

if to_address != 'Cancellation':
    try:
        amount_xrp = int(to_address["TakerGets"])/1000000.0
    except KeyError:
        pass

我可以不使用多个例外吗？

3 个答案: