Question

试图弄清楚如何做到以下几点： sum(case when count(goal_id) over (partition by user_id) > 1 then 1 else 0 end) as user_with_multiple_goals。显然不支持此功能-但我不希望以任何方式不添加更多子查询。

有什么建议吗？

表格：

user_id goal_id
A       A
A       B
A       C
B       D
C       E
C       F

输出： 2

Answer 1

根据您的示例数据，可以将其简化为正常情况/计数：

SELECT user_id, 
       CASE WHEN COUNT(*) > 1 
            THEN 1 
            ELSE 0 
       END as user_with_multiple_goals
FROM yourTable
GROUP BY user_id

发布修改：

SELECT DISTINCT COUNT(*)
FROM yourTable
GROUP BY user_id
HAVING COUNT(*) > 1

Answer 2

我在想：

select count(*)
from (select user_id, count(*) as num_goals
      from t
      group by user_id
     ) u
where num_goals > 1;

或者：

select count(distinct user_id)
from t
where exists (select 1 from t t2 where t2.user_id = t.user_id and t2.goal_id <> t.goal_id);

如何替换sum（count（）over（x分区））

2 个答案: