解决这个问题是我的解决方案:
修改:已更新,以反映抢劫案的答案。
import com.google.android.maps.GeoPoint;
import com.google.android.maps.MapView;
import com.google.android.maps.Overlay;
import com.google.android.maps.Projection;
import android.content.Context;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.Point;
public class CircleOverlay extends Overlay {
Context context;
double mLat;
double mLon;
float mRadius;
public CircleOverlay(Context _context, double _lat, double _lon, float radius ) {
context = _context;
mLat = _lat;
mLon = _lon;
mRadius = radius;
}
public CircleOverlay(Context _context, double _lat, double _lon, float radius ) {
context = _context;
mLat = _lat;
mLon = _lon;
mRadius = radius;
}
public void draw(Canvas canvas, MapView mapView, boolean shadow) {
super.draw(canvas, mapView, shadow);
if(shadow) return; // Ignore the shadow layer
Projection projection = mapView.getProjection();
Point pt = new Point();
GeoPoint geo = new GeoPoint((int) (mLat *1e6), (int)(mLon * 1e6));
projection.toPixels(geo ,pt);
float circleRadius = projection.metersToEquatorPixels(mRadius) * (1/ FloatMath.cos((float) Math.toRadians(mLat)));
Paint innerCirclePaint;
innerCirclePaint = new Paint();
innerCirclePaint.setColor(Color.BLUE);
innerCirclePaint.setAlpha(25);
innerCirclePaint.setAntiAlias(true);
innerCirclePaint.setStyle(Paint.Style.FILL);
canvas.drawCircle((float)pt.x, (float)pt.y, circleRadius, innerCirclePaint);
}
}
要“绘制”,需要将其添加到地图叠加层
mMapView.getOverlays().add(new CircleOverlay(context, loc.getLatitude(),loc.getLongitude()));
希望这有帮助。
答案 0 :(得分:8)
接受的答案有错误。我试图纠正它,但我的编辑因某些奇怪的原因被拒绝了。无论如何,这是一个更正的答案:
import com.google.android.maps.GeoPoint;
import com.google.android.maps.MapView;
import com.google.android.maps.Overlay;
import com.google.android.maps.Projection;
import android.content.Context;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.Point;
public class CircleOverlay extends Overlay {
Context context;
double mLat;
double mLon;
float mRadius;
public CircleOverlay(Context _context, double _lat, double _lon, float radius ) {
context = _context;
mLat = _lat;
mLon = _lon;
mRadius = radius;
}
public CircleOverlay(Context _context, double _lat, double _lon, float radius ) {
context = _context;
mLat = _lat;
mLon = _lon;
mRadius = radius;
}
public void draw(Canvas canvas, MapView mapView, boolean shadow) {
super.draw(canvas, mapView, shadow);
if(shadow) return; // Ignore the shadow layer
Projection projection = mapView.getProjection();
Point pt = new Point();
GeoPoint geo = new GeoPoint((int) (mLat *1e6), (int)(mLon * 1e6));
projection.toPixels(geo ,pt);
float circleRadius = projection.metersToEquatorPixels(mRadius) * (1/ FloatMath.cos((float) Math.toRadians(mLat)));
Paint innerCirclePaint;
innerCirclePaint = new Paint();
innerCirclePaint.setColor(Color.BLUE);
innerCirclePaint.setAlpha(25);
innerCirclePaint.setAntiAlias(true);
innerCirclePaint.setStyle(Paint.Style.FILL);
canvas.drawCircle((float)pt.x, (float)pt.y, circleRadius, innerCirclePaint);
}
}
Scott的答案中的问题是,circleRadius是使用一种方法计算的,该方法将米的值转换为像素的点数。但是,如果您想要的点不在赤道上,则半径将太小,因为转换不能说明经络在极点处聚集在一起的事实。但是,这可以通过乘以(1/ FloatMath.cos((float) Math.toRadians(mLat)))
来纠正,这是我对斯科特原始答案所做的唯一更改。
我希望这有助于某人,因为我发现问题的方法很艰难。我住在芬兰,在那里使用原始方法,画出的圆圈比原来的要小2倍!
答案 1 :(得分:7)
我已经采用了上面的示例并对其进行了扩展,以考虑需要使用地图缩放级别缩放的圆圈(即:相对于地面距离的圆圈)。
有些人可能觉得它很有用。
import com.google.android.maps.GeoPoint;
import com.google.android.maps.MapView;
import com.google.android.maps.Overlay;
import com.google.android.maps.Projection;
import android.content.Context;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.Point;
public class CircleOverlay extends Overlay {
Context context;
double mLat;
double mLon;
float mRadius;
public CircleOverlay(Context _context, double _lat, double _lon, float radius ) {
context = _context;
mLat = _lat;
mLon = _lon;
mRadius = radius;
}
public void draw(Canvas canvas, MapView mapView, boolean shadow) {
super.draw(canvas, mapView, shadow);
if(shadow) return; // Ignore the shadow layer
Projection projection = mapView.getProjection();
Point pt = new Point();
GeoPoint geo = new GeoPoint((int) (mLat *1e6), (int)(mLon * 1e6));
projection.toPixels(geo ,pt);
float circleRadius = projection.metersToEquatorPixels(mRadius) * (1/ FloatMath.cos((float) Math.toRadians(mLat)));
Paint innerCirclePaint;
innerCirclePaint = new Paint();
innerCirclePaint.setColor(Color.BLUE);
innerCirclePaint.setAlpha(25);
innerCirclePaint.setAntiAlias(true);
innerCirclePaint.setStyle(Paint.Style.FILL);
canvas.drawCircle((float)pt.x, (float)pt.y, circleRadius, innerCirclePaint);
}
}
答案 2 :(得分:0)
您要尝试显示的地理位置点(0.1275,51.507222)?这是在索马里沿海的某个地方。
super.draw(..)
应该是draw()
方法中的第一个语句。
答案 3 :(得分:0)
在 onMapReady()回调中添加以下代码。
Java
map.addCircle(new CircleOptions()
.center(new LatLng(latitude, longitude))
.radius(10000.0f)
.strokeColor(Color.BLUE)
.fillColor(Color.CYAN));
科特林
map.addCircle(CircleOptions()
.center(LatLng(latitude, longitude))
.radius(10000.0f)
.strokeColor(Color.BLUE)
.fillColor(Color.CYAN))