Question

下面的代码应该让用户输入：

名称
好/坏牙齿

程序应允许用户将其输入数组并循环10次，然后以表格格式（您可以在代码底部找到的格式）输出该列表。

import java.util.Scanner;

public class pbclass;
{
    public static void main(String[] args)
    {
        pbclass objectt = new pbclass();
        objectt.dentistpractice();
    }

    public void dentistpractice()
    {
        Scanner scan = new Scanner(System.in);
        String[] patientFamName = new String[10];
        String[] patientFirstName = new String[10];
        String[] PatientGoodTeeth = new String[10];
        String[] PatientBadTeeth = new String[10];

        for(int i = 0; i < 10; ++i)
        {
            System.out.println("Enter surname name ");
            patientFamName[i] = scan.nextLine();
            if (patientFamName[i].equalsIgnoreCase("close") ==true)
            {
                break;
            }
            System.out.println("Enter first name ");
            patientFirstName[i] = scan.nextLine();
            System.out.println("Enter good teeth ");
            PatientGoodTeeth[i] = scan.nextLine();
            int numconverterForHomeTeam = Integer.parseInt(PatientGoodTeeth[i]);
            System.out.println("Enter score for away team: ");
            PatientBadTeeth[i] = scan.nextLine();
            int numconverterForAwayTeam = Integer.parseInt(PatientBadTeeth[i]);
    }
    System.out.println(patientFamName[0] + patientFirstName[0] + " ||||||| " +PatientGoodTeeth[0]  + PatientBadTeeth[0] );
    System.out.println(patientFamName[1] + patientFirstName[1] + " ||||||| " +PatientGoodTeeth[1]  + PatientBadTeeth[1] );

}

我面临的问题是我不知道如何以简单的方式输出数据。如果数组是1000个变量甚至更长的话该怎么办？

此外，如何防止在显示表上显示“ null”。如果用户键入“ exit”，则循环应停止并显示已输入的数据（不包括空值）。

Answer 1

这将做您想要的。但是您可以改善打印结果部分。

import java.util.ArrayList;
    import java.util.Scanner;

    public class pbclass {
        public static void main(String[] args) {
            pbclass objectt = new pbclass();
            objectt.dentistpractice();
        }

        Scanner scan = new Scanner(System.in);
         int array_length=10;
         int array_length2=0;
        String[] patientFamName = new String[array_length];
        String[] patientFirstName = new String[array_length];
        Integer[] PatientGoodTeeth = new Integer[array_length];
        Integer[] PatientBadTeeth = new Integer[array_length];



        public void dentistpractice() {


            for (int i = 0; i < array_length; ++i) {
                System.out.println("Enter surname name ");
                patientFamName[i] = scan.nextLine();
                if (patientFamName[i].equalsIgnoreCase("close")) {
                    break;
                }
                array_length2++;
                System.out.println("Enter first name ");
                patientFirstName[i] = scan.nextLine();
                System.out.println("Enter good teeth ");
                PatientGoodTeeth[i] = scan.nextInt();
                scan.nextLine();
                System.out.println("Enter score for away team: ");
                PatientBadTeeth[i] = scan.nextInt();
                scan.nextLine();
            }
            for(int i = 0; i < array_length2; ++i){
                System.out.println("-----------------------");
                System.out.println(" | " +patientFamName[i] + " | "+ patientFirstName[i] + " | " + PatientGoodTeeth[i] + " | "+ PatientBadTeeth[i]+ " | ");
            }
            System.out.println("-----------------------");

        }
    }

使用system.out从循环JAVA

1 个答案: