Question

我有来自请求的数组。我想验证一下。例如。如果我有数组，

$array = ['red', 'yellow', 'green', 'red'];

$request = ['colour' => 'red'];

在上述情况下，它应该通过验证，因为请求值在给定数组中多次出现。

Answer 1

因此，根据您的新规格和已修改的问题：

<?php

$array = ['red', 'yellow', 'green', 'red'];

$request = ['colour' => 'red'];

// Error counter
$errors = 0;

// If request shows up in the array.. move to next block
if( in_array( $request['colour'], $array ) ){

  /* Check how many times this key value shows up,then assign to count 
     variable.
     In this example, $request['colour'] is red
     array_count_values($arr) returns an array 
        $array['red'=> 2,'yellow'=> 1,...], so 
     show me the **count** in this array at array_key position for "red", 
     being two.
    */
    $count = array_count_values( $array )[ $request['colour'] ];
    // if this count is more than 1, increment our error flag for use later
    if ($count > 1){
        $errors++;
        echo "Ut oh, this value shows up more than once in our array";
    }

}

或为简单起见：

$count = array_count_values( $array )[ $request['colour'] ];

if ($count > 1){ $errors++; }

echo $errors;

Answer 2

如果我正确理解您的问题，我想这就是您想要的http://php.net/manual/en/function.array-unique.php

$array = ['red','red','yellow','green'];
$arr = array_unique($array);
// $arr would now be ['red','yellow','green'];

如果我误解了，这将为您提供数组中出现的次数 http://us2.php.net/manual/en/function.array-count-values.php

Answer 3

如果要计数数组中每个项目的计数，可以使用array_count_values。

这将返回带有键“ red”和值2的数组。

var_dump(array_count_values($arr));

如果只希望“ red”作为输出，则可以使用array_diff来排序所有1的值。

$array = ['red', 'yellow', 'green', 'red'];

$counts = array_count_values($array);
$oneOrMore = array_diff($counts, [1]);

var_dump($oneOrMore);

//array(1) {
//   ["red"]=>int(2)
//}

https://3v4l.org/FNYLS

必需的正则表达式，以避免请求的值在给定数组中多次出现

3 个答案: