Spring Boot返回400缺少的构造函数没有堆栈跟踪

时间:2018-10-22 16:54:39

标签: java spring spring-mvc spring-boot

我有一个带有

的帖子
public Test postTest(@RequestBody Test test) {
}


public class Test {
    @JsonProperty("EMAIL_ADDRESS")
    @NotNull(message = "EMAIL_ADDRESS_NOT_NULL")
    @Size(min = 1, message = "EMAIL_ADDRESS_NOT_EMPTY")
    @Email(flags = Flag.CASE_INSENSITIVE, message = "EMAIL_INVALID")
    private String emailAddress;

    public ForgetPassword(
            @NotNull(message = "EMAIL_ADDRESS_NOT_NULL") @Size(min = 1, 
            message = "EMAIL_ADDRESS_NOT_EMPTY") @Email(flags = 
            Flag.CASE_INSENSITIVE, 
            message = "EMAIL_INVALID") String emailAddress) {
        super();
        this.emailAddress = emailAddress;
    }

    public String getEmailAddress() {
        return emailAddress;
    }

    public void setEmailAddress(String emailAddress) {
        this.emailAddress = emailAddress;
    }
}

我缺少默认的构造函数,并且在尝试发布时,它始终返回错误的请求。如果我添加默认构造函数,则可以使用。它甚至不会抛出堆栈跟踪。我正在使用自定义模板来发送回响应。我重写了BadRequestException以发送回自定义消息。

@ResponseStatus(HttpStatus.BAD_REQUEST)
public class BadRequestException extends RuntimeException {
    public BadRequestException(String message) {
        super(message);
    }
}

是否有任何我应该重写的方法来捕获此类异常。我想知道为什么出问题了,并且能够看到堆栈痕迹。

2 个答案:

答案 0 :(得分:1)

您可以使用@ControllerAdvice定义全局异常处理程序。您可以使用@ExcecptionHandler在此处放置尽可能多的处理程序。您可以记录errorTrace进行调试。

package com.startwithjava.exception;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.MethodArgumentNotValidException;
import org.springframework.web.bind.annotation.ControllerAdvice;
import org.springframework.web.bind.annotation.ExceptionHandler;

@ControllerAdvice
public class ApiExceptionHandler {
    @ExceptionHandler(Exception.class)
    public ResponseEntity<Object> handlerGenericError(Exception ex){
        ex.printStackTrace();
        return new ResponseEntity<>(ex.getMessage(), HttpStatus.INTERNAL_SERVER_ERROR);
    }
    @ExceptionHandler(BadRequestException.class)
    public ResponseEntity<Object> handlerBadRequest(BadRequestException ex){
        return new ResponseEntity<>(ex.getMessage(), HttpStatus.NOT_FOUND);
    }
}

答案 1 :(得分:1)

您可以声明一个如下所示的类来处理异常。

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.http.HttpStatus;
import org.springframework.web.bind.annotation.ControllerAdvice;
import org.springframework.web.bind.annotation.ExceptionHandler;
import org.springframework.web.bind.annotation.ResponseStatus;

@ControllerAdvice
public class GlobalExceptionHandler {
    private static Logger LOGGER = LoggerFactory.getLogger(GlobalExceptionHandler.class);

    @ExceptionHandler(Exception.class)
    @ResponseStatus(value=HttpStatus.INTERNAL_SERVER_ERROR, reason="Error processing the request, please check the logs")
    public void handleException(Exception e) {
        LOGGER.error("Exception occurred", e);
    }
}