如何将重复的记录汇总到查询结果中的特定记录

Question

在查询结果中，我得到了特定策略中用于驾驶员的重复车辆，并且在我的初始查询中结果还不错。这是我的结果：

从上面的图片中，我只想显示POLICYHOLDER的车辆记录，并在同一策略中从ACTIVE记录中删除这些相同的车辆。这就是我希望的样子：

这是我的sql代码：

WITH CTE1 as 
(
SELECT pr1.*
FROM #tempPIFRecords pr1
), 
CTE2 as (
SELECT pavr.*
FROM #tempPIFAssocVehicleRecords pavr
)

SELECT CTE1.*, CTE2.Year, CTE2.Make, CTE2.Model, CTE2.[Effective Date], CTE2.[Expiration Date]
FROM CTE1
LEFT OUTER JOIN CTE2
ON CTE1.AgentNo = CTE2.AgentNo
AND CTE1.PolicyNo = CTE2.PolicyNo
ORDER BY CTE1.AgentNo asc, CTE1.PolicyNo asc;

任何帮助/指导将不胜感激。谢谢。

Answer 1

应该可以：

WITH CTE1 as 
(
SELECT pr1.*
FROM #tempPIFRecords pr1
), 
CTE2 as (
SELECT pavr.*
FROM #tempPIFAssocVehicleRecords pavr
)

SELECT CTE1.*, ISNULL(CTE2.Year, '') AS Year, ISNULL(CTE2.Make, '') AS MAke, ISNULL(CTE2.Model, '') AS Model, ISNULL(CTE2.[Effective Date], '') AS [Effective Date], ISNULL(CTE2.[Expiration Date], '') AS [Expiration Date]
FROM CTE1
LEFT OUTER JOIN CTE2
ON CTE1.AgentNo = CTE2.AgentNo
AND CTE1.PolicyNo = CTE2.PolicyNo
AND CTE1.[DriverType] = 'PolicyHolder'
ORDER BY CTE1.AgentNo asc, CTE1.PolicyNo asc;