Question

我正在尝试开发一个计分板网站，该网站将反映用户及其各自的分数，但是由于我对django框架和python并不熟悉，因此我面临着很多开发方面的问题。

>

在我遇到错误的记分牌代码下面。如果有人遇到或开发了记分牌，请帮助我解决代码。谢谢！

models.py

var input = new HashSet<int>(); // accepts only unique values

while (input.Count() < 5)
{
    Console.WriteLine("enter value");

    int temp; // In newer C# it can be moved to TryParse e.g "out int temp"
    if (Int32.TryParse(Console.ReadLine(), out temp))
    {
        if (input.Contains(temp))
        {
            Console.WriteLine("this number is already in collection");
        }
        else
        {
            input.Add(temp);
        }
    }
    else
    {
        Console.WriteLine("incorrect value");
    }
}
// order by(lambda_expression) allows you to specify by "what things" 
// you'd want to order that collection. In this case you're just sorting 
// by numbers, but if it was complex objects collection then you'd be
// able to sort by e.g student => student.Money; which would mean that 
// you're sorting students by their Money count.
foreach (var number in input.OrderBy(x => x))
{
    Console.WriteLine(number);
}

Answer 1

您犯了两个错误，一个是在模型 priority 中添加了所有与外键相关的名称，并注释了member1_choice和Consult_choice代码，请运行 python manage.py makemigrations 命令之后，您将注释掉该代码，因为它已创建了依赖项。

我修改了您的代码，请看看。

class member1(models.Model):
      name = models.CharField(max_length=100)

    def __str__(self):
        return self.name + ',' + self.contact_number + ',' + self.yourpost + " , " + str(self.department).upper()


class Score(models.Model):
    granted_by = models.ForeignKey(member1, default=0)
    granted_to = models.ForeignKey(member1, default=0, related_name="granted_to")

class priority(models.Model):
    link = models.ForeignKey(member1, on_delete=models.CASCADE, related_name='priority_link')
    score = models.ForeignKey(member1, on_delete=models.CASCADE,      related_name='priority_score')
    name = models.ForeignKey(member1, on_delete=models.CASCADE, related_name='priority_name')
    def __str__(self):
        return str(self.link) + ',' + str(self.number)
    def alpha_name(self):
        return str(self.link.name)

    def score(self):
        return str(score)


member1_choice = [
    i.tuple() for i in member1.objects.all()
]

consult_choice = [
i.tuple() for i  in consultant.objects.all()
]

尝试开发使用django框架反映用户和得分的Web门户

1 个答案: