Question

这是我的CSV：

AAP,AAMC,AAPL,AMT

106.08999633789062,,,

,122.88999938964844,,

,,109.80000305175781,

,,,118.55000305175781

由于所有的'，'和换行符，我的第二行被打印在楼梯上。如何使用python获取同一行缩进的所有数据？

我尝试使用.replace函数，但是每次都需要进行硬编码。有没有办法找到模式以便于：

因此预期输出如下：

AAP,AAMC,AAPL,AMT
106.08999633789062,122.88999938964844,109.80000305175781,118.55000305175781

Answer 1

尝试一下：

import csv
data = {}
with open('input.txt') as input_file:
    reader = csv.DictReader(input_file, delimiter=',')
    for row in reader:
        for key, value in row.items():
            if value:
                data[key] = value
with open('output.txt', 'w', newline='') as output_file:
    writer = csv.DictWriter(output_file, delimiter=',', fieldnames=data.keys())
    writer.writeheader()
    writer.writerow(data)

数据是：

{'AAMC': '122.88999938964844',
 'AAP': '106.08999633789062',
 'AAPL': '109.80000305175781',
 'AMT': '118.55000305175781'}

Output.txt：

AAP,AAMC,AAPL,AMT
106.08999633789062,122.88999938964844,109.80000305175781,118.55000305175781

Answer 2

这里是一种方法：

import pandas as pd

df = pd.read_csv('a.csv')
m = df.max()
print(list(m.keys())); print(list(m.values))
# => ['AAP', 'AAMC', 'AAPL', 'AMT']
# => [106.08999633789062, 122.88999938964844, 109.8000030517578, 118.5500030517578]

Answer 3

您可以尝试以下代码：

import pandas as pd 
df=pd.read_csv("a.csv",delimeter=',',skipinitialspace=True,delim_whitespace=True)
print(list(df.keys()))
print(list(df.values()))
df.to_csv("b.csv",index=False)

如何在逗号之间删除空格和逗号之间的多余逗号并将其替换为''

3 个答案: