Question

考虑这个简单的类：

<?php declare(strict_types=1);

class Blog
{
    private $user;

    public function __construct(string $user)
    {       
        $this->user = $user;    
    }

    public function post ()
    {
        return 'New post by '.$this->user;      
    }
}

使用基本的依赖注入可以正常工作：

$blog = new Blog('Bob');
echo $blog->post();
// no errors, works as expected

$blog = new Blog(7);
echo $blog->post();
// fatal errors with TypeError, works as expected

但是当使用诸如league\container之类的依赖项容器时，strict_types声明会被忽略吗？

$container = new League\Container\Container;
$container->add(Blog::class)->addArgument(7);
$foo = $container->get(Blog::class);
echo $foo->post();
// I passed `7` in the parameter, it doesn't work as expected
//  because it should've fatal error with TypeError because `7` is not a string

对src的{{1}}文件夹的快速浏览显示，该文件的所有文件也都使用league\container。也就是说，我不确定容器是否有可能检测其启动的类的参数类型。如果不可能，那么在这种情况下使用declare(strict_types=1);是没有用的吗？

结合使用strict_types = 1和无用的依赖容器？

0 个答案: