Question

以下是Train类的代码：

class Train(pygame.sprite.Sprite):
def __init__(self):
    pygame.sprite.Sprite.__init__(self) #call Sprite initializer
    self.image, self.rect = load_image('train.bmp', -1)
    ...

这是我在主循环中创建单个列实例的地方：

trains = pygame.sprite.Group()
while True:
    for event in pygame.event.get():
        if event ...:
            train = Train()
            train.add(trains)

如何让每个火车实例都独一无二？

Answer 1

您的代码会创建一个变量列，但从不使用train * s *。我将变量重命名为train_list以使其更清晰。

train_list = pygame.sprite.Group()
done = False # any code can toggle this , to request a nice quit. Ie ESC

while not done:
    for event in pygame.event.get():
        if event ...:
            train = Train()
            train_list.add(train)

阅读docs: pygame.sprite.Group 并piman's sprite pygame tutorial

如果我想更改其中一列的变量怎么办？

# modify a variable on one train
train_list[2].gas = 500

# kill train when out of gas
for cur in train_list:
    # this will call Sprite.kill , removing that one train from the group.
    if cur.gas <= 0:
        cur.kill()

如何更新所有列车？

你可以定义Train.update，使用gas，因为SpriteGroup.update调用了Sprite.update

Train(pygame.sprite.Sprite):
    def __init__(self):
        super(Train, self).__init__()
        self.gas = 100
    def update(self)
        self.gas -= 1 # or you can use a variable from the caller

Answer 2

实际上，如果您需要识别火车，您可以为每一个火车添加一个ID：

class Train(pygame.sprite.Sprite):
    def __init__(self, ID = None):
        # train goes here, maybe even a counter that changes "ID" to something if not user-defined.

然后将它们循环遍历：

for train in trains:
    if ID == "whatever you like":
        #Do something

！伪代码！

如何创建一个对象的多个唯一实例并使用python和pygame将它们添加到列表中？

2 个答案: