Question

我将php表单用于sql数据视图。问题是我想查看顶部的最新数据和最后的旧数据。可以帮我吗？这是我的php表单查看代码。这里的所有详细信息用于从sql获取数据。和它的工作正常，但需要从新到旧查看。

<table cellpadding="0" cellspacing="0" border="0" class="datatable table table-striped table-bordered">
    <thead>
      <tr>
        <th>S.No</th>
        <th class="wraper-title">Notice Title</th>
        <th>Publish Date</th>
        <th>Type</th>
        <th>View</th>
        <th>Delete</th>
        <th>Download</th>
      </tr>
    </thead>
    <tbody>
    <?php
      while($r = mysqli_fetch_assoc($result)){
     ?>
      <tr>
        <th scope="row"><?php echo $r['id'] ?></th>
        <td class="wraper-title"><?php echo $r['name'] ?></td>
        <td><?php echo $r['date'] ?></td>
        <td><?php echo $r['type'] ?></td>
        <td>
          <a type="button" class="btn btn-success" href="<?php echo $r['location'] ?>">View</a>
        </td>
        <td>
          <a type="button" class="btn btn-danger delete" title="Delete this notice" href="#" onclick='DeleteFile(<?php echo $r['id'] ?>)'><i class="glyphicon glyphicon-trash"></i></a>
        </td>
        <td>
          <a type="button" class="btn btn-primary download" href="<?php echo $r['location'] ?>" title="Download <?php echo $r['name'] ?>" download="<?php echo $r['name'] ?>" {%=file.thumbnailUrl?'data-gallery':''%}><i class="glyphicon glyphicon-download"></i></a>
        </td>
      </tr>
      <?php
      }
      ?>
    </tbody>
    <tfoot>
        <tr>
          <th>S.No</th>
          <th class="wraper-title">Notice Title</th>
          <th>Publish Date</th>
          <th>Type</th>
          <th>View</th>
          <th>Delete</th>
          <th>Download</th>
        </tr>
      </tfoot>
   </table>

请帮助我

Answer 1

您可以尝试使用此功能。这将按升序对第一和第二列进行排序。

其中0和1是列的索引

$('#table_id').dataTable( {
    "order": [[ 0, 'asc' ], [ 1, 'asc' ]]
});

想要在顶部和旧数据中最后查看sql最新数据。表示最新的版本

1 个答案: