下面的代码创建一个从1〜9的结构数组作为顶点,然后接受顶点所指向的其余部分。例如,如果某人输入1作为主顶点,那么他将允许输入一个图形的多个节点。但是,我目前面临着第三个while循环和最后一个while循环的问题。对于这一部分,它应该检测到下一个为NULL并退出,但这会给我一个EXC_BAD_ACCESS错误。
#include <stdio.h>
#include <stdlib.h>
struct node{
int data;
struct node* next;
};
int main(){
struct node *G[10];
for (int i = 1; i < 10; i++)
{
G[i]= malloc(sizeof(struct node));
G[i]->data = i;
G[i]->next = NULL;
printf("%i\n", G[i]->data);
}
int input = 10;
int vertixBeingModi=1;
printf("Please enter your vertix you want to modify? \n");
scanf("%i", &vertixBeingModi);
while(vertixBeingModi != 0){
while (input != 0){
printf("Please enter the edges ? \n");
scanf("%i", &input);
struct node* cursor;
struct node* newItem;
cursor = G[vertixBeingModi];
if (input == 0){
break;
}
while(cursor->next != NULL )
{
cursor = cursor->next;
}
newItem = malloc(sizeof(struct node));
cursor->next = newItem;
newItem->data = input;
cursor = G[vertixBeingModi];
}
printf("Please enter your vertix you want to modify? \n");
scanf("%i", &vertixBeingModi);
input = 1;
if (vertixBeingModi == 0){
break;
}
}
int array[10];
struct node* tempDegree;
int counter = 0;
for(int x = 1; x < 10; x++){
tempDegree = G[x];
if(tempDegree->next == NULL){
continue;
}else{
while(tempDegree->next != NULL ){
counter = counter + 1;
tempDegree = tempDegree->next;
}
array[x] = counter;
counter = 0;
}
}
printf("%d\n", array[1]);
}
答案 0 :(得分:1)
您只是忘记了初始化newItem->next
:
while (cursor->next != NULL)
{
cursor = cursor->next;
}
newItem = malloc(sizeof(struct node));
newItem->next = NULL; // <<<<<<<<<<<< add this line
cursor->next = newItem;
newItem->data = input;
cursor = G[vertixBeingModi];