分配向量值

时间:2018-10-21 21:43:30

标签: c++ vector assign

我正在研究一个简单的骰子游戏项目,该项目需要我实例化一个自定义类的多个副本。

vector <Player> playerList;

playerList.resize(totalNumPlayers); //totalNum is grabbed from cin

for (int x = 0; x < totalNumPlayers; x++) 
{
    playerList.at(x).setname("Player" + to_string(x + 1));
    //playerList[x] = p;
    playerList.at(x).printName();
    cout << playerList[0].returnName() << " " << playerList[1].returnName() << " " << playerList[2].returnName() << endl;
}

玩家职业:

//Declarations
string playerName;
int playerChips;

Player::Player()
{
    //Default constructor for when player is created
    playerChips = 3;
    playerName = "DEFAULT_PLAYER_NAME";
}

void Player::setname(string var)
{
    playerName = var;
}

string Player::returnName()
{
    return(playerName);
}

void Player::printName()
{
    cout << playerName << endl;
}

void Player::addChips(int x)
{
    playerChips += x;
}

void Player::removeChips(int x)
{
    playerChips -= x;
}

int Player::returnChips()
{
    return(playerChips);
}

我注意到,在原始forloop期间的每次迭代中,playerList [x]值始终相同。例如,如果totalNumPlayers = 3,则playerList [0],playerList [1]和playerList [2]都受setName行的影响。因此,当我对PL 1,2和3使用cout时,它总是打印

玩家1,玩家1,玩家1 然后 播放器2,播放器2,播放器2

为什么对每个索引的引用对于它们自己的对象不是唯一的?

1 个答案:

答案 0 :(得分:1)

原因很简单。您已经在全局名称空间中定义了string playerName;(尚未提供源文件的完整结构),因此,每当调用Player::setname时,都将修改此全局变量,从而在调用时Player::printName()在for循环中,您只需读取在Player的所有实例之间共享的变量。要解决此问题,请将此变量移至Player类中:

class Player
{
private: 
    string playerName;
public:
    Player();
    void setname(string var);
    string returnName();
    string Player::returnName();
    void printName();
    void addChips(int x);
    void printName();
    // and the rest of your declarations
};