如何从Mobiscroll子组件获取引用到父组件

时间:2018-10-21 19:00:58

标签: reactjs mobiscroll

我正在尝试将孩子的状态归为父。将Child的状态和方法移到父级后,我得到以下信息:

export default class Parent extends React.Component {
  constructor() {
    super();
    this.state = { mpc_steps: { price: 0, credits: 0, text: "MPC Credits" } }
  }

  setMPCSteps = () => {
    let step = this.refs.mpc_slider.instance.getVal(); // Will fail
    this.setState({
      mpc_steps: { 
        price: step * 200, 
        credits: step, 
        text: "MPC Credits" 
      }
    });
  };

  render() {
    return(
      <div>
        <Child getCredits={this.setMPCSteps} getParentState={this.state.mpc_steps}/>
    )
  }
}

子组件:

export default class Child extends React.Component {
  render() {
    return (
      <Fragment>
        <mobiscroll.Slider
          ref="mpc_slider"
          value={this.props.getParentState}
          onChange={this.props.getCredits}
        >
          Buy Credits @ $2/Credit
        </mobiscroll.Slider>
      </Fragment>
    )
  }
}

我需要以某种方式从父级调用子级的ref值。问题在于,mobiscroll ref不是从父级定义的。有一个简单的方法吗?欢迎任何提示。

1 个答案:

答案 0 :(得分:1)

您可以使用React.forwardRef api

子组件:

class Child extends React.Component {
  render() {
    return (
      <Fragment>
        <mobiscroll.Slider
          ref={this.props.innerRef}
          value={this.props.getParentState}
          onChange={this.props.getCredits}
        >
          Buy Credits @ $2/Credit
        </mobiscroll.Slider>
      </Fragment>
    )
  }
}

export default React.forwardRef((props, ref) => <Child innerRef={ref} {...props}/>);

并像这样使用它:

<Child ref="mpc_slider" />