Question

我有以下@RestContoller可以登录：

  @RequestMapping("/account/login")
@ResponseBody
@CrossOrigin(origins = "*", maxAge = 3600)
public Principal login(Principal principal) {
    logger.info("user logged " + principal.getName());
    return principal;
}

我有一个来自Angularjs应用程序的客户端的以下请求。

Accept: application/json
Accept-Encoding: gzip, deflate, br
Accept-Language: en-US,en;q=0.9,fa;q=0.8,it;q=0.7
Authorization: Basic bWVocmRhZGFsbGFoa2FyYW1pQGdtYWlsLmNvbTptZWhyZGFk
Connection: keep-alive
DNT: 1
Host: localhost:8080
Origin: http://localhost:4200
Referer: http://localhost:4200/login
User-Agent: Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.62 Safari/537.36

但是我得到200的响应，服务器打印null，而客户端得到错误的响应：

HttpErrorResponse {headers: HttpHeaders, status: 400, statusText: "OK", url: "http://localhost:8080/account/login", ok: false, …}error: {timestamp: 1540136257516, status: 400, error: "Bad Request", exception: "org.springframework.web.bind.ServletRequestBindingException", message: "Missing request header 'header' for method parameter of type Header", …}headers: HttpHeaders {normalizedNames: Map(0), lazyUpdate: null, lazyInit: ƒ}message: "Http failure response for http://localhost:8080/account/login: 400 OK"name: "HttpErrorResponse"ok: falsestatus: 400statusText: "OK"url: "http://localhost:8080/account/login"__proto__: HttpResponseBase

任何人都可以帮助我知道我哪里做错了吗？以前可以使用，但是我在Angular中使用了拦截器，但现在无法使用了。

我的登录控制器是：

@Injectable()
export class AuthService {
  constructor(public http: HttpClient, public auth: InterceptorAuthService) {
  }

  public logIn(user: User) {
    this.auth.setUser(user);
    return this.http.get(AppComponent.API_URL + "/account/login")
      .pipe(
        map(response => {
            // login successful if there's a jwt token in the response
            let user = response;// the returned user object is a principal object
            if (user) {
              // store user details  in local storage to keep user logged in between page refreshes
              localStorage.setItem('currentUser', JSON.stringify(user));
            }
          },
          catchError(error => {
            return Observable.throw(error);
          })
        ));
  }
}

WebConfig.java配置：

// This method is used for override HttpSecurity of the web Application.
// We can specify our authorization criteria inside this method.
@Override
protected void configure(HttpSecurity http) throws Exception {
    // @formatter:off
    // ignoring the guest's urls "
    http.antMatcher("/account/**").authorizeRequests().anyRequest().authenticated().and()
            .antMatcher("/token").authorizeRequests().anyRequest().authenticated()
            .antMatchers("/logout").permitAll()
            .and()
            .csrf()
            .csrfTokenRepository(CookieCsrfTokenRepository.withHttpOnlyFalse()).and()
            .httpBasic();
    // authenticate all remaining URLS

    // @formatter:on
}

Answer 1

尝试在要显示用户名的“ / account / login”模板中添加sec:authorize="isAuthenticated()

例如：

<h3 sec:authorize="isAuthenticated()" th:text="${user.username}"></h3>

如果它已经发生，它将获得认证状态，否则，它不会显示<h3>代码块。

Answer 2

@Component
public class MyBasicAuthenticationEntryPoint extends BasicAuthenticationEntryPoint {
@Override
public void afterPropertiesSet() throws Exception {
    setRealmName("Baeldung");
    super.afterPropertiesSet();
}
@Override
public void commence(
  HttpServletRequest request, HttpServletResponse response, AuthenticationException authEx) 
  throws IOException, ServletException {
    response.addHeader("WWW-Authenticate", "Basic realm="" + getRealmName() + """);
    response.setStatus(HttpServletResponse.SC_UNAUTHORIZED);
    PrintWriter writer = response.getWriter();
    writer.println("HTTP Status 401 - " + authEx.getMessage());
}
}

// inside filter we can get the 
SecurityContextHolder.getContext().getAuthentication().getPrincipal()

主体为空：Spring

2 个答案: