Question

我希望将一个字符串（例如：0.1.2）转换为char字符串（它变为：abc）。错误在哪里？谁能帮我。谢谢！

let alphacode = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27];
let alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'];

function uncrypt(stringToUncrypt) {
    let temp = new Array();
    temp = stringToUncrypt.split(".");
    for (let i = 0; i < temp.length; i++) {
        //console.log('Questa è la stringa senza il PUNTO: ' + temp[i]);
    }

    //console.log('contenuto di temp: ' + temp);
    let result = [];
    //console.log('contenuto di result: ' + result);

    for (let j in temp) {
        //console.log('siamo dentro let j in temp:' + temp[j]);
        for (let x in alphacode) {
            //console.log('siamo dentro let x in alphacode:' + alphacode[x]);
            for (let z in alphabet) {
                if (temp[j] === alphacode[x]) {
                    alphacode[x] = alphabet[z];
                    console.log('contenuto di alphabet [z]' + alphabet[z]);
                    result += alphabet[z];
                }
            }
        }
    }
    console.log('----------UNCRYPTED----------')
    return 'Risultato: ' + result;
}

let text = uncrypt('0.1');
console.log(text);

Answer 1

仅对代码进行少量修改。您太复杂了。

let alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'];

function uncrypt(stringToUncrypt) {
    const temp = stringToUncrypt.split("."); // no need to initialize the variable to an empty array, just set it to the splitted string directly
    let result = ''; // as you want a string as output, it makes sense to directly work with strings here
    for (let j of temp) { // use for..of to iterate over the characters inside the array, e.g. "0", "1"
        result += alphabet[parseInt(j)]; // take the char as a position in the alphabet, e.g. alphabet[0] -> "a"
    }
    console.log('----------UNCRYPTED----------')
    return 'Risultato: ' + result;
}

let text = uncrypt('0.1');
console.log(text);

在我的解决方案中，存储在temp中的数字对应于alphabet数组的索引。

Answer 2

    let alphacode = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '11', '12', '13', '14', '15', '16', '17', '18', '19', '20', '21', '22', '23', '24', '25', '26', '27'];
    let alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'];

    function uncrypt(decodedString) {
        const chars = decodedString.split(".");
        return chars.map(char => alphabet[alphacode.indexOf(char)]).join("");
        
    }

    let text = uncrypt('0.1');
    console.log('Risultato: ' + text);

map帮助遍历数组，并用alphacode中的匹配代码替换并返回当前值。

Answer 3

由于您在代码result中声明的是一个数组，因此需要将答案push放入其中，而不是像字符串那样将其串联起来：

result.push(alphabet[z]);

然后，要使用正确的格式获取从函数返回的字符串，应使用join：

return 'Risultato: ' + result.join('');

但是，您的代码中使用了太多的循环。您只需要一个：

let alphacode = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '11', '12', '13', '14', '15', '16', '17', '18', '19', '20', '21', '22', '23', '24', '25', '26', '27'];
let alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'];

function uncrypt(stringToUncrypt) {
  let temp = stringToUncrypt.split(".");
  let result = [];

  // loop over the split string ONLY
  for (let i = 0; i < temp.length; i++) {

    // Get in the index of the current element in the
    // alphacode array
    const index = alphacode.indexOf(temp[i]);

    // Push the corresponding element with that index from
    // alphabet into the result array
    result.push(alphabet[index]);
  }
  return 'Risultato: ' + result.join('');
}

let text = uncrypt('0.1');
console.log(text); // ab

DEMO

Answer 4

function uncrypt(stringToUncrypt) {
  let alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'];

   return stringToUncrypt.split(".").map(i => alphabet[i-1]).join('');
}

做你想要的事的简短方法

将由点分隔的int字符串转换为char字符串

4 个答案: