我有一些lng,lat
的坐标数据,但是我需要lat,lng
我将它们包含在元组列表中,并且需要在它们之间进行切换:
myList = [(-87.93897686650001, 41.8493707892),
(-87.93893322819997, 41.8471652588),
(-87.9292710931, 41.8474548975),
(-87.91960917239999, 41.8477438951),
(-87.91927828050001, 41.8404034535)]
我尝试过
newList = []
for i in range(len(myList)):
for c, x in reversed(list(enumerate(myList[i]))):
newList.append(x)
我得到以下输出,这是关闭的
[41.8493707892,
-87.93897686650001,
41.8471652588,
-87.93893322819997,
41.8474548975,
-87.9292710931,
41.8477438951,
-87.91960917239999,
41.8404034535,
-87.91927828050001]
但是我正在寻找
[(41.8493707892, -87.93897686650001),
(41.8471652588, -87.93893322819997),
(41.8474548975, -87.9292710931),
(41.8477438951, -87.91960917239999),
(41.8404034535, -87.91927828050001)]
理想情况下,我想在嵌套的for循环中完成所有操作;但是我不在乎是否需要对newList进行分组。
一如既往地感谢您的帮助。
答案 0 :(得分:2)
除非您真的很喜欢嵌套的for循环,否则使用这种列表理解可能最简单:
newlist=[i[::-1] for i in myList]
>>> newlist
[(41.8493707892, -87.93897686650001), (41.8471652588, -87.93893322819997), (41.8474548975, -87.9292710931), (41.8477438951, -87.91960917239999), (41.8404034535, -87.91927828050001)]
答案 1 :(得分:0)
您可以通过列表理解非常容易地做到这一点。
[(b,a) for a,b in myList]