Question

我收到的错误是：

_csv。错误：迭代器应返回字符串，而不是字节（您是否以文本模式打开文件？）

我将在文本代码中的什么位置打开文件？

import csv
import urllib.request
import pymysql.cursors
connection = pymysql.connect(host='localhost',
                         user='',
                         password='',
                         db='mydb',
                         charset='utf8',
                         cursorclass=pymysql.cursors.DictCursor)
try:
    url = 'https://api.iextrading.com/1.0/stock/market/collection/sector?
    collectionName=Health%20Care&format=csv'
    response =  urllib.request.urlopen(url)
    csv_data = csv.reader(response)
    for row in csv_data:

    cursor.execute('INSERT INTO Financials (names, \
          classes, mark )' \
          'VALUES("%s", "%s", "%s")', 
          row)
finally:
    connection.close()

Answer 1

@RestController
public class UserController {

    private UserService userService;

    @Autowired
    public UserController(UserService userService) {
        this.userService = userService;
    }

    @PostMapping("/api/auth/signup")
    public ResponseEntity<RestResponse> registerUser(@Valid @RequestBody SignUpRequest signUpRequest,
                                                     UriComponentsBuilder uriComponentsBuilder)  {
        RestResponse restResponse = this.userService.register(signUpRequest);
        UriComponents uriComponents = uriComponentsBuilder.path("/users").buildAndExpand();
        return ResponseEntity.created(uriComponents.toUri()).body(restResponse);
    }

    @PostMapping("/api/auth/signin")
    public ResponseEntity<JwtAuthenticationResponse> authenticateUser(@Valid @RequestBody LoginRequest loginRequest) {
        return ResponseEntity.ok(this.userService.login(loginRequest));
    }
}

此处response = urllib.request.urlopen(url)返回response对象上的迭代器。

如果您知道csv文件只是纯文本，则可以插入生成器理解以解码行：

bytes

或csv_data = csv.reader(line.decode() for line in response)（当您不使用map就可以使用python 3 map吗？）

lambda

独立的示例：

csv_data = csv.reader(map(bytes.decode,response))

现在您要向import urllib.request,csv url = 'https://api.iextrading.com/1.0/stock/market/collection/sector?collectionName=Health%20Care&format=csv' response = urllib.request.urlopen(url) for row in csv.reader(line.decode() for line in response): print(row)提供一系列字符串，这将起作用。

示例输出：

csv.reader

CSV返回为字节而不是字符串Python

1 个答案: