Question

我正在尝试编写一个程序来计算用户输入的数字的平均值。

用户可以输入任意数量的数字，直到输入0，这会中断[while]循环。

我遇到的困难是我不知道如何告诉程序求和一组未知的数字。

我花了数小时试图弄清楚这一点（我是编程的新手）。我将不胜感激。

#include <stdio.h>

int main() {

    int numberEntered;
    int sum = 0;

    printf("Program to calculate the average of a series of numbers\n\n");
    printf("Please enter the first number. Enter 0 to stop: ");

    scanf("%d", &numberEntered);
    while (numberEntered != 0)
    {
        sum = sum + numberEntered;
        printf("Please enter another number. Enter 0 to stop: ");
        scanf("%d", &numberEntered);
    }
}

Answer 1

您快完成了。只需count个元素的数量和divide sum乘count即可得到average。这里也需要type-casting，否则2和3中的average会给您2，这是不正确的。

#include <stdio.h>

    int main() {
    int numberEntered;
    int sum = 0;

    printf("Program to calculate the average of a series of numbers\n\n");
    printf("Please enter the first number. Enter 0 to stop: ");
    scanf("%d", &numberEntered);

    int count_number = 0;

    while (numberEntered != 0)
    {
    sum = sum + numberEntered;
    count_number++;
    printf("Please enter another number. Enter 0 to stop: ");
    scanf("%d", &numberEntered);
    }
    if(count_number>0)
       {printf("AVG: %f",((float)sum)/count_number);}

    }

Answer 2

您可能还希望保持输入计数，并在打破while循环后最后将总和除以该数字。

程序来计算C中未知数集的平均值

2 个答案: