我已成功发送简单的电子邮件:
SimpleMailMessage mailMessage = new SimpleMailMessage();
mailMessage.setTo("someone@abc.com");
mailMessage.setSubject("This is the test message for testing gmail smtp server using spring mail");
mailMessage.setFrom("abc@gmail.com");
mailMessage.setText("This is the test message for testing gmail smtp server using spring mail. \n" +
"Thanks \n Regards \n Saurabh ");
mailSender.send(mailMessage);
我需要什么设置才能发送html电子邮件
答案 0 :(得分:73)
import javax.mail.internet.MimeMessage;
import org.springframework.mail.javamail.MimeMessageHelper;
MimeMessage mimeMessage = mailSender.createMimeMessage();
MimeMessageHelper helper = new MimeMessageHelper(mimeMessage, false, "utf-8");
String htmlMsg = "<h3>Hello World!</h3>";
mimeMessage.setContent(htmlMsg, "text/html");
helper.setTo("someone@abc.com");
helper.setSubject("This is the test message for testing gmail smtp server using spring mail");
helper.setFrom("abc@gmail.com");
mailSender.send(mimeMessage);
答案 1 :(得分:17)
我不认为SimpleMailMessage类有这样的选项。
我确信您可以使用JavaMailSender和MimeMessagePreparator来完成,因为您需要为HTML设置MIME内容类型。
请参阅此链接以获取帮助:
http://static.springsource.org/spring/docs/3.0.x/spring-framework-reference/html/mail.html
答案 2 :(得分:16)
在春天,这应该这样做:
您的电子邮件类:
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.mail.MessagingException;
import javax.mail.internet.MimeMessage;
import org.springframework.mail.SimpleMailMessage;
import org.springframework.mail.javamail.JavaMailSender;
import org.springframework.mail.javamail.MimeMessageHelper;
public class HTMLMail
{
private JavaMailSender mailSender;
public void setMailSender(JavaMailSender mailSender) {
this.mailSender = mailSender;
}
public void sendMail(String from, String to, String subject, String msg) {
try {
MimeMessage message = mailSender.createMimeMessage();
message.setSubject(subject);
MimeMessageHelper helper;
helper = new MimeMessageHelper(message, true);
helper.setFrom(from);
helper.setTo(to);
helper.setText(msg, true);
mailSender.send(message);
} catch (MessagingException ex) {
Logger.getLogger(HTMLMail.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
<强>豆:强>(弹簧Mail.xml)
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
<bean id="mailSender" class="org.springframework.mail.javamail.JavaMailSenderImpl">
<property name="host" value="smtp.gmail.com" />
<property name="port" value="587" />
<property name="username" value="youremail@gmail.com" />
<property name="password" value="yourpassword" />
<property name="javaMailProperties">
<props>
<prop key="mail.smtp.auth">true</prop>
<prop key="mail.smtp.starttls.enable">true</prop>
</props>
</property>
</bean>
<bean id="htmlMail" class="com.mohi.common.HTMLMail">
<property name="mailSender" ref="mailSender" />
</bean>
</beans>
<强>用法:强>
ApplicationContext context = new ClassPathXmlApplicationContext("Spring-Mail.xml");
HTMLMail mm = (HTMLMail) context.getBean("htmlMail");
String html="<p>Hi!</p><a href=\"google.com\">Link text</a>";
mm.sendMail("sender@gmail.com",
"receiver@gmail.com",
"test html email",
html);
完整示例here。
答案 3 :(得分:9)
您可能有兴趣查看这篇文章: “Spring with Thymeleaf中的Rich HTML电子邮件” http://www.thymeleaf.org/doc/articles/springmail.html
它使用Thymeleaf作为模板视图层,但是所解释的概念和特定于Spring的代码对于所有Spring应用程序都是通用的。
此外,它还有一个配套示例应用程序,您可以根据需要使用源代码。
此致 丹尼尔。
答案 4 :(得分:4)
班级级别:
public String sendEmailToUsers(String emailId,String subject, String name){
String result =null;
MimeMessage message =mailSender.createMimeMessage();
try {
MimeMessageHelper helper = new MimeMessageHelper(message, false, "utf-8");
String htmlMsg = "<body style='border:2px solid black'>"
+"Your onetime password for registration is "
+ "Please use this OTP to complete your new user registration."+
"OTP is confidential, do not share this with anyone.</body>";
message.setContent(htmlMsg, "text/html");
helper.setTo(emailId);
helper.setSubject(subject);
result="success";
mailSender.send(message);
} catch (MessagingException e) {
throw new MailParseException(e);
}finally {
if(result !="success"){
result="fail";
}
}
return result;
}
XML级别:
<bean id="mailSender" class="org.springframework.mail.javamail.JavaMailSenderImpl">
<property name="host" value="smtp.gmail.com" />
<property name="port" value="587" />
<property name="username" value="********@gmail.com" />
<property name="password" value="********" />
<property name="javaMailProperties">
<props>
<prop key="mail.transport.protocol">smtp</prop>
<prop key="mail.smtp.auth">true</prop>
<prop key="mail.smtp.starttls.enable">true</prop>
</props>
</property>
</bean>
答案 5 :(得分:0)
String emailMessage = report.toString();
Map velocityContext = new HashMap();
velocityContext.put("firstName", "messi");
velocityContext.put("Date",date );
velocityContext.put("Exception",emailMessage );
String text = VelocityEngineUtils.mergeTemplateIntoString(velocityEngine, "VelocityTemplate.vm","UTF-8", velocityContext);
MimeMessage message = mailSender.createMimeMessage();
MimeMessageHelper helper;
helper = new MimeMessageHelper(message, true);
helper.setTo("abc@gmail.com");
helper.setFrom("xyz@gmail.com");
helper.setSubject("new email");
helper.setText(text, true);
mailSender.send(message);