Question

我有表orders (order_id, order_processed_date)。我想要最近12个月每月的订单数。如果任何月份有0个订单，则应打印0。

类似这样的东西：

Total Orders | Month
-----------------------
2            | OCT 2018
3            | SEP 2018
0            | AUG 2018
0            | JUL 2018
1            | JUN 2018
0            | MAY 2018
0            | APR 2018
0            | MAR 2018
5            | FEB 2018
5            | JAN 2018
0            | DEC 2017
0            | NOV 2017

我已经在该网站中搜索并获得了一些查询，但没有找到确切的解决方案。我使用以下查询获得结果，但没有年份：

SELECT 
SUM(IF(month = 'Jan', total, 0)) AS 'Jan',
SUM(IF(month = 'Feb', total, 0)) AS 'Feb',
SUM(IF(month = 'Mar', total, 0)) AS 'Mar',
SUM(IF(month = 'Apr', total, 0)) AS 'Apr',
SUM(IF(month = 'May', total, 0)) AS 'May',
SUM(IF(month = 'Jun', total, 0)) AS 'Jun',
SUM(IF(month = 'Jul', total, 0)) AS 'Jul',
SUM(IF(month = 'Aug', total, 0)) AS 'Aug',
SUM(IF(month = 'Sep', total, 0)) AS 'Sep',
SUM(IF(month = 'Oct', total, 0)) AS 'Oct',
SUM(IF(month = 'Nov', total, 0)) AS 'Nov',
SUM(IF(month = 'Dec', total, 0)) AS 'Dec'
FROM (SELECT DATE_FORMAT(order_processed_date, '%b') AS month, 
COUNT(order_id) as total
FROM orders
WHERE order_processed_date <= NOW() and order_processed_date >= 
Date_add(Now(),interval - 12 month)
GROUP BY DATE_FORMAT(order_processed_date, '%m-%Y')) as sub

能否请我帮忙给我结果。

Answer 1

以下查询建立了前12个月的每月第一天的列表。例如，在Oct 19 2018上，列表将包含从Oct 01 2018到Nov 01 2017的日期。剩下的事由左联接完成：

SELECT date, COUNT(orders.primary_key)
FROM (
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH AS date UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 2 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 3 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 4 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 5 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 6 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 7 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 8 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 9 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 10 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 11 MONTH UNION ALL
    SELECT LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 12 MONTH
) AS dates
LEFT JOIN orders ON order_processed_date >= date AND order_processed_date < date + INTERVAL 1 MONTH
GROUP BY date

MySQL查询可获取按月分组的最近12个月的数据，包括零计数

1 个答案: