我有一个这样的列表L1=[]
L2=[]
def big_data(query,x,y):
x = []
r = requests.get("http://bigdata.com/metrics/?" + query)
r0 = r.json()[0][u'datapoints']
returned_data = r0[17:]
for datapoint1 in returned_data:
x.append(datetime.fromtimestamp(datapoint1[1]).strftime('%I%P').lstrip('0').upper())
y =[item[0] for item in returned_data]
print(x)
print(y)
big_data(domain,L1,L2)
print(L1)
print(L2)
When I am running above script I am able to getting a value for x and y but its not giving me anything for L1 and L2.
I am not able to recall what basic thing I am missing here, Can someone please let me know what I am missing here.
Output I am getting is something like this:-
x = ['4PM', '5PM', '6PM', '7PM']
y = [291783, 3090123, 2736213, 105331]
L1 = []
L2 = []
我有一个列为“ file_name”的数据框
有没有办法使用python列表过滤行？
我知道
['1.jpg','222.jpg','333.jpg']但这需要手动编码每个值，而不是使用for循环。
答案 0 :(得分：2)
尝试：
df_filtered = df[(df.file_name.isin([['1.jpg','222.jpg','333.jpg']])]
答案 1 :(得分：0)
这应该有效：
df_filtered = df[df['file_name'].isin(['1.jpg','222.jpg','333.jpg'])]