我创建了变量timer_loop以连续运行。我想使用其他变量进行条件语句,但是我无法这样做。下面是一个示例,如果开关被激活,我将尝试每30分钟执行一次“操作”。任何反馈将不胜感激:)
from kivy.app import App
from kivy.lang import Builder
from kivy.clock import Clock
import datetime
import time
theRoot = Builder.load_string('''
StackLayout:
orientation: 'lr-tb'
padding: 10
spacing: 5
Label:
text: "Zone 1 Valve"
size_hint: .5, .1
Switch:
id: switch_id
on_active: app.switch_on1(self, self.active)
size_hint: .5, .1
''')
class theApp(App):
def build(self):
Clock.schedule_interval(self.timer_loop, 2)
return theRoot
def timer_loop(self, dt):
now_minute = int(time.strftime("%M"))
if switch_on1.active & now.minute ==30 : # how do I use the varible switch_on1 in this loop for conditonal statements???
print("Do something")
else:
print("Do nothing")
def switch_on1(self, instance, value):
if value is True:
print("Switch 1 On")
else:
print("Switch 1 Off")
if __name__ == '__main__':
theApp().run()
答案 0 :(得分:0)
始终建议将类视为黑箱,我们可以建立输入并获得输出,并且可以通过属性来完成,例如,在这种情况下,您创建了StackLayout
的活动属性,反映了switch_id的活动属性,由于theRoot
是StackLayout
对象,可以从python看到它,所以我们使用它:
from kivy.app import App
from kivy.lang import Builder
from kivy.clock import Clock
import time
theRoot = Builder.load_string('''
StackLayout:
active: switch_id.active # <---
orientation: 'lr-tb'
padding: 10
spacing: 5
Label:
text: "Zone 1 Valve"
size_hint: .5, .1
Switch:
id: switch_id
size_hint: .5, .1
''')
class theApp(App):
def build(self):
Clock.schedule_interval(self.timer_loop, 2)
return theRoot
def timer_loop(self, dt):
now_minute = int(time.strftime("%M"))
if theRoot.active and now_minute == 30: # <---
print("Do something")
else:
print("Do nothing")
if __name__ == '__main__':
theApp().run()
您意识到没有必要使用switch_on1
,因为主要条件是计时器的触发。