Question

我正在通过从今天的日期中减去其年龄来计算用户的年龄。我的问题是，它显示了他们的年龄整数。但是，我不想将其显示为整数，而是将其显示为小数，例如25.5或27.3。我尝试使用round和number_format，但都没有用。

$bday = $data->_field_data['node_field_data_field_game_players_nid']['entity']->field_player_birthday['und'][0]['value'];
$now = date("Y/m/d");
$diff = ($now) - date($bday);
echo number_format(round($diff, 2), 2);

Answer 1

您可以尝试以下操作：

$bday = $data->_field_data['node_field_data_field_game_players_nid']['entity']->field_player_birthday['und'][0]['value'];
echo  number_format(round((strtotime(date('Y-m-d')) - strtotime($bday))/(60*60*24*365),2),2);

但是，以上计算非常粗糙。如果您想更精确地获取价值，则应使用date_diff来实现：

$bday = $data->_field_data['node_field_data_field_game_players_nid']['entity']->field_player_birthday['und'][0]['value'];
$date1=date_create($bday); //create date object
$date2=date_create(date("Y-m-d")); //create date object
$curyearmaxdays=date("z", mktime(23,59,59,12,31,date("y")))+1; //count of days in the current year
$diff = date_diff($date1, $date2); //difference between two date objects
$realdiff=$diff->y + $diff->m/12+$diff->d/$curyearmaxdays;
echo  number_format(round($realdiff,2),2);

计算日期差

1 个答案: