Question

我正在尝试从要爬网的数据创建结构化JSON对象。

我抓取的数据存储在几个列表中。 list1包含事件名称，list2包含事件类别，list3包含原始事件数据（以与事件类别相同的顺序存储）

list1 = [['event1'], ['event2'], ['event3']]
list2 = [['team' , 'score', 'date'], ['team', 'location', 'date'], ['team', ' record']]
list3 = [['team1' , 'score1', 'date1', 'team2' , 'score2', 'date2'],
         ['team1' , 'location1', 'date1', 'team2' , 'location2', 'date2'],
         ['team1', 'record 1', 'team2', 'record2', 'team3', 'record3']]

我正在尝试创建以下格式的json文件：

{
  "event1": {
          "1": {
                  "team": team1,
                  "score": score1,
                  "date": date1,
               },
          "2": {
                  "team": team2,
                  "score": score2,
                  "date": date2,
               },

            },
  "event2": {
          "1": {
                  "team": team1,
                  "location": location1,
                  "date": date1,
               },
          "2": {
                  "team": team2,
                  "location": location2,
                  "date": date2,
               },
  "event3": {
          "1": {
                  "team": team1,
                  "record": record1,
               },
          "2": {
                  "team": team2,
                  "record": record2,
               },
          "3": {
                  "team": team3,
                  "record": record3,
               },
}

是否可以在python上以这种方式进行结构化？我可以使用其他语言的for循环来做到这一点，但是我在如何用python附加数据方面颇费心思。

Answer 1

希望我能理解我的解决方案。

list1 = [['event1'], ['event2'], ['event3']]
list2 = [['team' , 'score', 'date'], ['team', 'location', 'date'], ['team', ' record']]
list3 = [['team1' , 'score1', 'date1', 'team2' , 'score2', 'date2'], ['team1' , 'location1', 'date1', 'team2' , 'location2', 'date2'], ['team1', 'record 1', 'team2', 'record2', 'team3', 'record3']]
out = {}
#iterate over each of the lists together
for (a,), b, c in zip(list1, list2, list3):
    #initialise the "event." attribute in the `out` dict
    out[a] = {}
    #chunk the lists in `list3` to the size of the lists in `list2` and iterate
    for i, l in enumerate([c[i:i+len(b)] for i in range(0, len(c), len(b))]):
        #for this chunk, initiate a sub dictionary under the "event." attr in `out`
        out[a][str(i+1)] = {}
        #iterate over the elements in the list from `list2`
        for j, e in enumerate(b):
            #assign the corresponding chunk element to the appropriate location.
            out[a][str(i+1)][e] = l[j]

给出：

{
    "event1": {
        "1": {
            "team": "team1",
            "score": "score1",
            "date": "date1"
        },
        "2": {
            "team": "team2",
            "score": "score2",
            "date": "date2"
        }
    },
    "event2": {
        "1": {
            "team": "team1",
            "location": "location1",
            "date": "date1"
        },
        "2": {
            "team": "team2",
            "location": "location2",
            "date": "date2"
        }
    },
    "event3": {
        "1": {
            "team": "team1",
            " record": "record 1"
        },
        "2": {
            "team": "team2",
            " record": "record2"
        },
        "3": {
            "team": "team3",
            " record": "record3"
        }
    }
}

如何从列表创建结构化JSON对象？

1 个答案: