Question

我已经建立了用户登录功能：

export const userLogin = (email, password) => (dispatch) => {
    console.log(email, password);
  dispatch({ type: actionTypes.AUTH_LOGIN_STARTED });
  console.log("after dispatch");
  Parse.User.logIn(email, password, {
    success(user) {
        console.log("in success");
      dispatch({
        type: actionTypes.AUTH_LOGIN_SUCCESS,
        user: user.toJSON(),
      });
     window.location.replace('/');
    },
    error(user, error) {
        console.log("in error")
      console.log({ error });
      // The login failed. Check error to see why.
      dispatch({
        type: actionTypes.AUTH_LOGIN_ERROR,
        error,
      });
    },
  });
};

，但是它总是在Parse.User.logIn之后卡住，它不会成功也不会出错。我已经记录了电子邮件和密码，它们是正确的。

那我在这里想念什么？

Answer 1

Parse.User.Login does not have any third parameter。您应该使用promise functions：

Parse.User.logIn(email, password)
  .then((user) => {
    console.log("in success");
    dispatch({
      type: actionTypes.AUTH_LOGIN_SUCCESS,
      user: user.toJSON(),
    });
    window.location.replace('/');
  })
  .error((user, error) => {
    console.log("in error")
    console.log({ error });
    // The login failed. Check error to see why.
    dispatch({
      type: actionTypes.AUTH_LOGIN_ERROR,
      error,
    });
  });

或者，如果您足够看中，可以使用新的await语法（我认为这样更简洁）：

export const userLogin = (email, password) => async (dispatch) => {
  console.log(email, password);
  dispatch({ type: actionTypes.AUTH_LOGIN_STARTED });
  console.log("after dispatch");

  try {
    const user = await Parse.User.logIn(email, password);
    console.log("in success");
    dispatch({
      type: actionTypes.AUTH_LOGIN_SUCCESS,
      user: user.toJSON(),
    });
    window.location.replace('/');
  } catch (error) {
    console.log("in error")
    console.log({ error });
    // The login failed. Check error to see why.
    dispatch({
      type: actionTypes.AUTH_LOGIN_ERROR,
      error,
    });
  }
};

Parse.User.logIn卡住

1 个答案: