如何打开iOS8的设备设置？

Question

我一直看到您可以使用

if UIApplication.shared.canOpenURL(settingsUrl) {
    UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
        print("Settings opened: \(success)")
    })
}

，但仅适用于iOS 10及更高版本。但是，对于iOS 8，我该怎么做？

Answer 1

UIApplication.openSettingsURLString将返回设置url字符串。

if let settingsURL = URL(string: UIApplication.openSettingsURLString),
    UIApplication.shared.canOpenURL(settingsURL) {
    UIApplication.shared.open(settingsURL, completionHandler: { (success) in
        print("Settings opened: \(success)")
    })
}

Answer 2

目前，我几乎看不到任何对iOS 8的应用程序支持。但是，如果您想知道，这里是答案：

let urlStr = "yourURL"
if let linkURL = URL(string: urlString), UIApplication.shared.openURL(URL) {
 UIApplication.shared.openURL(linkURL)
}

Answer 3

这是对我有用的

if UIApplication.openSettingsURLString != nil{
    if let aString = URL(string: UIApplication.openSettingsURLString){
        UIApplication.shared.openURL(aString)
    }
}