好的，我正在尝试做的链接列表程序有问题，
链接列表工作正常。
这是我的代码
#include <iostream>
using namespace std;
struct record
{
string word;
struct record * link;
};
typedef struct record node;
node * insert_Node( node * head, node * previous, string key );
node * search( node *head, string key, int *found);
void displayList(node *head);
node * delete_node( node *head, node * previous, string key);
int main()
{
node * previous, * head = NULL;
int found = 0;
string node1Data,newNodeData, nextData,lastData;
//set up first node
cout <<"Depature"<<endl;
cin >>node1Data;
previous = search( head, node1Data, &found);
cout <<"Previous" <<previous<<endl;
head = insert_Node(head, previous, node1Data);
cout <<"Depature inserted"<<endl;
//insert node between first node and head
cout <<"Destination"<<endl;
cin >>newNodeData;
previous = search( head, newNodeData, &found);
cout <<"Previous" <<previous<<endl;
head = insert_Node(head, previous, newNodeData);
cout <<"Destinationinserted"<<endl;
//insert node between second node and head
cout <<"Cost"<<endl;
cin >>newNodeData;
previous = search( head, newNodeData, &found);
cout <<"Previous" <<previous<<endl;
head = insert_Node(head, previous, newNodeData);
cout <<"Cost inserted"<<endl;
cout <<"Number of Seats Required"<<endl;
//place node between new node and first node
cin >>nextData;
previous = search( head, nextData, &found);
cout <<"Previous" <<previous<<endl;
head = insert_Node(head, previous, nextData);
cout <<"Number of Seats Required inserted"<<endl;
//insert node between first node and head
cout <<"Name"<<endl;
cin >>newNodeData;
previous = search( head, newNodeData, &found);
cout <<"Previous" <<previous<<endl;
head = insert_Node(head, previous, newNodeData);
cout <<"Name inserted"<<endl;
//insert node between node and head
cout <<"Address "<<endl;
cin >>newNodeData;
previous = search( head, newNodeData, &found);
cout <<"Previous" <<previous<<endl;
head = insert_Node(head, previous, newNodeData);
cout <<"Address inserted"<<endl;
//place node as very last node
cin >>lastData;
previous = search( head, lastData, &found);
cout <<"Previous" <<previous<<endl;
head = insert_Node(head, previous, lastData);
cout <<"C"<<endl;
displayList(head);
char Ans = 'y';
//Delete nodes
do
{
cout <<"Enter Keyword to be delete"<<endl;
cin >>nextData;
previous = search( head, nextData, &found);
if (found == 1)
head = delete_node( head, previous,nextData);
displayList(head);
cout <<"Do you want to Delete more y /n "<<endl;
cin >> Ans;
}
while( Ans =='y');
int choice, i=0, counter=0;
int fclass[10];
int coach[10];
printf("Welcome to the booking program");
printf("\n-----------------");
do{
printf("\n Please pick one of the following option:");
printf("\n 1) Reserve a first class seat on Flight 101.");
printf("\n 2) Reserve a coach seat on Flight 101.");
printf("\n 3) Quit ");
printf("\n ---------------------------------------------------------------------");
printf("\nYour choice?");
scanf("%d",&choice);
switch(choice)
{
case 1:
i++;
if (i <10){
printf("Here is your seat: %d " , fclass[i]);
}
else if (i = 10)
{
printf("Sorry there is no more seats on First Class. Please wait for the next flight");
}
break;
case 2:
if (i <10){
printf("Here is your Seat Coach: %d " , coach[i]);
}
else if ( i = 10)
{
printf("Sorry their is no more Seats on Coach. Please wait for the next flight");
}
break;
case 3:
printf("Thank you and goodbye\n");
//exit(0);
}
} while (choice != 3);
}
/*******************************************************
search function to return previous position of node
******************************************************/
node * search( node *head, string key, int *found)
{
node * previous, * current;
current = head; previous = current;
*found = 0;//not found
//if (current->word < key) move through links until the next link
//matches or current_word > key
while( current !=NULL)
{
//compare exactly
if (key ==current->word )
{
*found = 1;
break;
}
//if key is less than word
else if ( key < current->word )
break;
else
{
//previous stays one link behind current
previous = current;
current = previous -> link;
}
}
return previous;
}
/********************************************************
display function as used with createList
******************************************************/
void displayList(node *head)
{
node * current;
//current now contains the address held of the 1st node similar //to head
current = head;
cout << "\n\n";
if( current ==NULL)
cout << "Empty List\n\n";
else
{
/*Keep going displaying the contents of the list and
set current to the address of the next node.
When set to null, there are no more nodes
*/
while(current !=NULL)
{
cout << current->word<<endl;
current = current ->link;
}
}
}
/************************************************************
insert node used to position node
(i) empty list head = NULL
(ii) to position node before the first node key < head->word
(iii) every other position including the end of the list
This is done using the following steps
(a) Pass in all the details to create the node either details or a whole record
(b) Pass the details over to fill the node
(C) Use the if statement to add the node to the list
**********************************************************/
node * insert_Node( node * head, node * previous, string key )
{
node * new_node, * temp;
new_node = new node; //create the node
new_node ->word = key;
new_node -> link = NULL;
if (head == NULL || key < head->word ) //empty list
{
//give address of head to temp
temp = head;
//head now points to the new_node
head = new_node;
//new_node now points to what head was pointing at
new_node -> link = temp;
}
else
{
//pass address held in link to temp
temp = previous-> link;
//put address of new node to link of previous
previous -> link = new_node;
//pass address of temp to link of new node
new_node -> link = temp;
}
return head;
}
node * delete_node( node *head, node * previous, string key)
{
/* this function will delete a node but will not return its
contents */
node * temp;
if(key == head->word) //delete node at head of list
{
temp = head;
//point head at the next node
head = head -> link;
}
else
{
//holds the address of the node after the one
// to be deleted
temp = previous-> link;
/*assign the previous to the address of the
present node to be deleted which holds
the address of the next node */
previous-> link = previous-> link-> link;
}
delete temp;
return head;
}//end delete
我遇到的问题是，当我输入节点（座位）中的数字2时，我想得到一个50的反击2，有些像我在这里的东西
enter code here
int choice, i=0, counter=0;
int fclass[10];
int coach[10];
printf("Welcome to the booking program");
printf("\n-----------------");
do{
printf("\n Please pick one of the following option:");
printf("\n 1) Reserve a first class seat on Flight 101.");
printf("\n 2) Reserve a coach seat on Flight 101.");
printf("\n 3) Quit ");
printf("\n ---------------------------------------------------------------------");
printf("\nYour choice?");
scanf("%d",&choice);
switch(choice)
{
case 1:
i++;
if (i <10){
printf("Here is your seat: %d " , fclass[i]);
}
else if (i = 10)
{
printf("Sorry there is no more seats on First Class. Please wait for the next flight");
}
break;
case 2:
if (i <10){
printf("Here is your Seat Coach: %d " , coach[i]);
}
else if ( i = 10)
{
printf("Sorry their is no more Seats on Coach. Please wait for the next flight");
}
break;
case 3:
printf("Thank you and goodbye\n");
//exit(0);
}
} while (choice != 3);
如何让用户在此功能中输入座位数
答案 0 :(得分：0)
我不确定你要求的是什么，但是如果我理解你的问题，那你就试图将2的值变为delete_node（）。
在示例代码中，您将用户输入读入整数。由于delete_node（）接受一个字符串作为其搜索参数，因此您只需要先将其转换。
无论哪种方式，请务必修复您的else if()语句。您需要(i == 10)而不是(i = 10)，因为您正在寻找平等，而不是分配。