Question

我最近才刚开始使用Java，这很糟糕。我真的很紧张。我需要弄清楚如何使用do-while循环将用户输入的1到10之间转换为星号。如果您能向我展示如何做到这一点，我将不胜感激。

System.out.println( "Enter number between one and ten: " );

示例：input = 7

预期输出：*******

如果数字不在1到10之间，则显示“重试”并再次询问

public class JavaApplication12  {

/**
* @param args the command line arguments
*/
public static void main(String[] args) throws Exception {
    Scanner in = new Scanner(System.in);
    System.out.println( "Enter number between one and ten: " );
    int count = in.nextInt();

    int counter = 0;

    if (count<1||count>10) {
        System.out.println("Try again");
        count = in.nextInt();
        System.out.print("*");
        counter++;
    }else{ 

       do {
          System.out.print("*");
          counter++;
       } while (counter < count);
    }
  }
}

Answer 1

这很容易。您需要在此处使用counter之类的变量，然后循环直到打印所有星星。最重要的是do while至少运行一次，因此您需要将counter初始化为零才能正常工作。相反，您可以从1开始并将条件更改为while (counter <= count)。
希望这就是您想要的：

    public static void main(String[] args) throws Exception {
        Scanner in = new Scanner(System.in);
        System.out.println( "Enter number between one and ten: " );
        int count = in.nextInt();
        int counter = 0;
        do {
            System.out.print("*");
            counter++;
        } while (counter < count);
    }

Answer 2

您必须在if块中删除多余的行。您的代码很好。

import java.util.Scanner;

public class JavaApplication12 {
  public static void main(String[] args) throws Exception {
    Scanner in = new Scanner(System.in);
    System.out.println( "Enter number between one and ten: " );
    int count = in.nextInt();
    int counter = 0;
    if (count<1||count>10) {
      System.out.println("Try again");
    }else{

      do {
        System.out.print("*");
        counter++;
      } while (counter < count);
    }
  }
}

如何通过do while循环将用户输入转换为星号？

2 个答案: