Question

我无法弄清楚如何将2d数组作为参数传递。我发现的C ++手册和其他示例并没有给我太多帮助，也许有人可以帮助我了解更多，如果他们看看我的代码。感谢

标题

#ifndef HEADER_H_INCLUDED
#define HEADER_H_INCLUDED


#include <iostream>
#include <iomanip>
#include <fstream>
#include <cctype>
#include <cstdlib>
#include <string>

using namespace std;

void extern readFile(ifstream&, int&, int&, int&, int&, int[][6]);
void extern userInput(int&, int&, int&, int&, int&, int&, char&, char&, int[][6]);
void extern findSeats(int&, int&, int&, int&, int&, int&, char&, char&, int[][6]);

#endif // HEADER_H_INCLUDED

主要

#include "header.h"

int main()

{
    ifstream inFile;
    int FC_Row, FC_Col, EconRow, EconCol, ticketNum, rowNum;
    int airplane[100][6];
    char ticketType, seatType;

    cout << setw(48) << "Thank you for choosing Cheeta Airlines!" << '\n' << '\n' << endl;
    ifstream inData;

    inData.open("Airplane.txt");

    if (!inData)
    {
        cout << "Cannot open the input file."
             << endl;
            return 1;
    }

    readFile(inFile, FC_Row, FC_Col, EconRow, EconCol, airplane[100][6]);
userInput(FC_Row, FC_Col, EconRow, EconCol, ticketNum, rowNum, ticketType, seatType,     airplane[100][6]);`

}

READFILE：

#include "header.h"

void readFile(ifstream& inFile, int& FC_Row, int& FC_Col, int& EconRow, int& EconCol, int airplane[][6])
{
    int a, b;

    inFile.open("Airplane.txt");

    inFile >> FC_Row >> FC_Col >> EconRow >> EconCol;

    for (a = 0; a < FC_Row; a++)
    for (b = 0; b < FC_Col; b++)
        inFile >> airplane[a][b] ;

    for (a = 0; a < EconRow; a++)
    for (b = 0; b < EconCol; b++)
        inFile >> airplane[a + FC_Row][b] ;

    cout << setw(11)<< "A" << setw(6) << "B"
    << setw(6) << "C" << setw(6) << "D"
    << setw(6) << "E" << setw(6) << "F" << endl;
    cout << " " << endl;

    cout << setw(30) << "First Class: $2,000" << endl;
    cout << '\n';
    for (a = 0; a < FC_Row; a++)
    {
        cout << "Row " << setw(2) << a + 1 << ":";
        for (b = 0; b < FC_Col; b++)
        cout << setw(5) << airplane[a][b] << " ";

        cout << endl;
    }

    cout << '\n';
    cout << setw(30) << "Economy Class: $750" << endl;
    cout << '\n';
    for (a = FC_Row; a < (EconRow + FC_Row); a++)
    {
        cout <<"Row " << setw(2)<< a + 1 << ":";
        for (b = 0; b < EconCol; b++)
        cout << setw(5) << airplane[a][b] << " ";

        cout << endl;
    }


}

Answer 1

如果您需要传递2D数组 -

void extern readFile(ifstream&, int&, int&, int&, int&, int[][6]);

void readFile(ifstream&, int&, int&, int&, int&, int[][6])
{
     // ....

}

呼叫应该是 -

readFile(inFile, FC_Row, FC_Col, EconRow, EconCol, airplane);

当你说 -

readFile(inFile, FC_Row, FC_Col, EconRow, EconCol, airplane[100][6]);

您实际上是在该位置传递值（即int）。但该函数需要int [][6]。

Answer 2

最后一个参数声明为int，但2D int数组的类型为int[][depth]。

将readFile原型声明更改为：

void extern readFile(ifstream&, int&, int&, int&, int&, int[][6]);

稍后，当您调用该函数时，您将传递数组int中的元素：

readFile(inFile, FC_Row, FC_Col, EconRow, EconCol, airplane[100][6]);

该函数需要一个类型为int[][6]的2D int数组，因此您必须只传递变量本身，而不传递任何索引：

readFile(inFile, FC_Row, FC_Col, EconRow, EconCol, airplane);

Answer 3

这些可能会引导您找到合适的解决方案

Passing multidimensional arrays as function arguments in C

http://c-faq.com/aryptr/ary2dfunc2.html

尝试将2d数组作为参数传递时未定义的引用

3 个答案: