Question

我在这里的代码中重新创建了问题。我可能没有正确定义列表。

import tkinter as tk
Name=("")
j=0
AnimalNameList=["Badger","Beaver","Buffalo","Bull","Bulldog","Cobra","Curlew","Eagle","Falcon","Fox","Gannet","Hawk","Kestrel","Lion","Merlin","Otter","Owl","Panther","Peewit","Raven","Seagull","Seal","Stag","Swift","Tiger","Wolf","Woodpecker","Woodpigeon"]
for i in AnimalNameList:
    j=j+1
    print(i)
print(j)
root=tk.Tk()
Animals=tk.OptionMenu(root,Name,AnimalNameList)
Animals.grid(row=1,column=1)
root.mainloop()

Answer 1

您可以测试它可以接受多少个值。

这是一个简单的例子：

import {Injectable} from "@angular/core";
import {HttpClient, HttpEvent, HttpHeaders, HttpParams, HttpRequest} from 
"@angular/common/http";

 @Injectable()
 export class PrestatairesService
  {
   host:string = "http://localhost:8080/";
   constructor(private http:HttpClient)
  {

  }

getAllTypes()
{
  return this.http.get(this.host + "prestatairesTypes");
}

 ajouterType(model:any)
 {
   return this.http.post(this.host + "prestatairesTypes", model);
 }

 getOneType(id:any)
 {
   return this.http.get(this.host + "prestatairesTypes/" + id);
 }

 ajouterPrestataires(model:any)
 {
   return this.http.post(this.host + "prestataires", model);
 }

 uploadFile(model:any)
 {

 let formData = new FormData();
 formData.append('multipartFile', model.file);
 formData.append('nom', model.nom);
 formData.append('email', model.email);
 formData.append('rib', model.rib);
 formData.append('taches', model.taches);
 formData.append('fax', model.fax);
  formData.append('adresse', model.adresse);

 // This is the line that cause the Error of status code 400
 // What to do here to send the request correctly
 formData.append('prestatairesTypes', model.prestatairesTypes);
 formData.append('tele', model.tele);

 let params = new HttpParams();

 const options = {
  params: params,
  reportProgress: true,
 };

 const req = new HttpRequest('POST', this.host+"prestataires", formData, 
  options);
 return this.http.request(req);
  }
 }

以上内容对我有用，尽管加载需要花费几秒钟。如果我尝试做70,000，它将失败。认为根据this post，列表中的max元素可能非常大，我认为限制可能是基于内存的。但是，您的问题并不是由于选择过多。

您在选项菜单上忘记了import tkinter as tk long_list = [] for i in range(50000): long_list.append(i) root = tk.Tk() Animals=tk.OptionMenu(root, "start", *long_list) Animals.grid(row=1, column=1) root.mainloop()作为参数。传递选项列表时，这是必需的，否则它将为您提供一个下拉菜单项，其中列表中的所有值都排在一行中。

所以改变这个：

为此：

Animals=tk.OptionMenu(root,Name,AnimalNameList)

还要确保您要进行Animals=tk.OptionMenu(root,Name,*AnimalNameList)，因为括号是必需的。

tkinter选项菜单是否可以代表最大数量的值？

1 个答案: