我有这段代码可以使用字典翻译字符串(以列表开头)。我希望代码转换字符串,然后将其取消转换回原始字符串。
这是到目前为止我得到的代码:
words = ['Abra', ' ', 'cadabra', '!']
clues = {'A':'Z', 'a':'z', 'b':'y', 'c':'x'}
def converter(words, clues):
words = ''.join(words)
for item in words:
if item in clues.keys():
words = words.replace(item, clues[item])
return words
def reversal(clues):
clues = {v: k for k, v in clues.items()}
print(clues)
x = converter(words, clues)
print(x)
reversal(clues)
x = converter(words, clues)
print(x)
仅会打印 “ Zyrz xzdzyrz!” “ Zyrz xdzyrz!” 我不确定为什么不打印: “ Zyrz xzdzyrz!” “阿布拉·卡达布拉!”
我的代码中是否有错误导致其以这种方式运行?我检查了线索,并在通过该功能后将其正确反转。我在做什么错了?
答案 0 :(得分:0)
Python在所有字符串上已经具有translate
方法,只需调用它即可!
def converter(text, clues, reverse=False):
if reverse:
clues = {v: k for k, v in clues.items()}
table = str.maketrans(clues)
return text.translate(table)
用法:
words = ['Abra', ' ', 'cadabra', '!']
clues = {'A':'Z', 'a':'z', 'b':'y', 'c':'x'}
# join the text into a single string:
x = ''.join(words)
# convert first
x = converter(x, clues)
print(x) # -> you get `Zyrz xzdzyrz!`
#back to original
x = converter(x, clues, reverse=True)
print(x) # -> you get `Abra cadabra!`
答案 1 :(得分:-1)
似乎您正在尝试在函数中进行字典操作。您的函数需要返回字典的反向版本,然后您需要在主目录中获取它:
# Your stuff here
def reversal(clues):
return {v: k for k, v in clues.items()}
x = converter(words, clues)
print(x)
clues_reversed = reversal(clues)
x = converter(words, clues_reversed)
print(x)