Question

我对AJAX + Rest + Spring boot + MySQL有问题。请求成功，但是响应为空，无论请求中使用的格式如何。实际上，请求有效负载显示[“ customer”：“ MyCustomer”]，所以我认为问题出在控制器上。

AJAX 函数ajax_ciudad（customer）{// onchange选中框

$.ajax({
    type: "POST",
    contentType: "application/json",
    url: "/api/ciudades",
    data: JSON.stringify(customer),
    dataType: 'json',
    cache: false,
    timeout: 600000,
        }).then(function(data) {
            DO SOMETHING.... 
           });
        });

}

控制器

@RestController
@RequestMapping
public class SearchController {
@Autowired
    private MyRepository myRepository;
    @PostMapping("/api/ciudades")
    public @ResponseBody List<?> getSedes(String customer){

        List<Canal> ciudades = myRepository.findBySede(customer);
        return ciudades;
    }


REPOSITORY
    @Query(value ="SELECT * FROM canal WHERE cliente = ?1", nativeQuery = true)
    List<Canal> findBySede(@Param("customer") String customer);

...总是返回一个空对象[]

enter image description here

我尝试了几种数据格式，我尝试使用.val（）获取Select值以获取字符串，使用.value获取html值。...如果我手动输入了myRepository.findBySede（ “ MyString”）ajax响应具有信息，但是当我传递值时它不起作用；我做错了什么？谢谢您的帮助

我的实体类

@Entity
@Table(name = "canal")
public class Canal { 

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Column(name = "idcanal", unique = true, nullable = false)
    int id;
    @Column(name = "cliente")
    String cliente;
    @Column(name = "ciudad")
    String ciudad;
    @Column(name = "sede")
    String sede;
    @Column(name = "canal")
    String canal;
    @Column(name = "ip_pe")
    String ip_pe;
    @Column(name = "nombre_pe")
    String nombre_pe;
    @Column(name = "ipwan_pe")
    String ipwan_pe;
    @Column(name = "puerto_pe")
    String puerto_pe    ;
    @Column(name = "ipwan_router")
    String ipwan_router;
    @Column(name = "enrutamiento")
    String enrutamiento;
    *****getters and setters****
     }

Answer 1

我希望您已经正确定义了您的仓库，并根据客户字符串返回了正确的数据。

从ajax "customer"传递为@Param，并像这样定义您的控制器，例如@RestController包括@Controller和@ResponseBody:

@RestController
public class SearchController {
    @Autowired
    private MyRepository myRepository;

    @PostMapping("/api/ciudades")
    public List<Canal> getSedes(@Param("customer") String customer){

        List<Canal> ciudades = myRepository.findBySede(customer);
        return ciudades;
    }

或者更好的方法，返回ResponseEntity。

@RestController
public class SearchController {
    @Autowired
    private MyRepository myRepository;

    @PostMapping("/api/ciudades")
    public ResponseEntity<?> getSedes(@Param("customer") String customer){

        List<Canal> ciudades = myRepository.findBySede(customer);
        return new ResponseEntity<>(ciudades , HttpStatus.OK);
    }

在仓库中这样定义您的方法：

@Repository|
public interface MyRepository extends CrudRepository<Canal, String> 

    @Query(value ="SELECT * FROM canal GROUP BY cliente", nativeQuery = true)
    List<Canal> findByIdcanal(); // works fines

  //I assume here you have canal table and cliente is column in it as you 
   running native query

    @Query(value ="SELECT * FROM canal WHERE cliente = ?1", nativeQuery = true)
    List<Canal> findBySede(String customer); // doesn't work

  //OR try this as JPQL if you have Canal is entity and cliente as string type in it.
    @Query(value ="Select c from Canal c WHERE c.cliente = :cliente")
    List<Canal> findBySede(@Param("cliente") String customer); 

   //OR simply have Named query I assume you have Canal and cliente string type

   List<Canal> findByCliente(String customer); 


}

更新，因为我检查了您的本机查询是否正常。

如果要在控制器中将客户（字符串）作为@RequestBody发送，请遵循以下步骤：

创建分类客户

public class Customer {
private String customer;

public String getCustomer() {
    return customer;
}

public void setCustomer(String customer) {
    this.customer = customer;
}

}

将请求处理为@RequestBody

@PostMapping("/api/ciudades")
public ResponseEntity<?> getSedes(@RequestBody Customer customer){

    List<Canal> ciudades = myRepository.findBySede(customer.getCustomer());
    return new ResponseEntity<>(ciudades , HttpStatus.OK);
}

如何将字符串参数传递给自定义存储库方法？

1 个答案: