Question

有人可以帮我一些代码来拼接数组并推送到新数组吗？我有一个数组

someArray = [{
  name: "Kristian",
  lines: "2,5,10"
}, {
  name: "John",
  lines: "1,19,26,96"
}, {
  name: "Kristian",
  lines: "2,58,160"
}, {
  name: "Felix",
  lines: "1,19,26,96"
}];

我想将name =拼接到Kristian并推送到新数组

Answer 1

您可以使用

Array.prototype.filter()

filter（）方法创建一个新数组，该数组包含所有通过提供的功能实现的测试的元素。

Array.prototype.splice()

splice（）方法通过删除现有元素和/或添加新元素来更改数组的内容。

var someArray = [{name:"Kristian", lines:"2,5,10"},{name:"John", lines:"1,19,26,96"},{name:"Kristian", lines:"2,58,160"},{name:"Felix", lines:"1,19,26,96"}];

var res = someArray.filter((p,i) => {
  if(p.name=="Kristian"){
    someArray.splice(i, 1); //remove the mached object from the original array
    return p;
  }
});

console.log(res);
console.log('----------------');
console.log(someArray);

Answer 2

您可以将.reduce()方法与.splice()一起使用：

let data = [
  {name:"Kristian", lines:"2,5,10"}, {name:"John", lines:"1,19,26,96"},
  {name:"Kristian", lines:"2,58,160"}, {name:"Felix", lines:"1,19,26,96"}
];
  
let result = data.reduce((r, c, i, a) => {
  if(c.name = 'Kristian')
    r.push(a.splice(i, 1));
  return r;
}, []);

console.log(result);
console.log(data);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

您可以混合使用filter和map：

const filtered = someArray.filter(obj => obj.name !== "Kristian")
const newArray = someArray.map(obj => obj.name === "Kristian")

已过滤将删除这些项目，而map将使用删除的项目创建一个新数组

如何从数组中删除对象并推送到新数组

3 个答案: