Question

我有这个数组

array:15 [▼
  0 => 0
  1 => 0
  2 => 0
  3 => "2018-10-20"
  4 => "2018-10-21"
  5 => "2018-10-22"
  6 => "2018-10-23"
  7 => "2018-10-24"
  8 => 0
  9 => 0
  10 => "2018-10-27"
  11 => "2018-10-28"
  12 => "2018-10-29"
  13 => "2018-10-30"
  14 => "2018-10-31"
]

，我想以某种方式将存在于零值之间的每一组值提取到一个单独的数组中。

我希望结果是类似的。

array:1 [▼
  0 => "2018-10-20"
  1 => "2018-10-21"
  2 => "2018-10-22"
  3 => "2018-10-23"
  4 => "2018-10-24"
]

array:2 [▼
 0 => "2018-10-27"
 1 => "2018-10-28"
 2 => "2018-10-29"
 3 => "2018-10-30"
 4 => "2018-10-31"
]

Answer 1

您可以使用foreach循环执行此操作：

$chunks = [];
$current_chunk = [];

foreach ($arr as $item) {
    if ($item == 0) {
        if (count($current_chunk) > 0) {
            $chunks[] = $current_chunk;
            $current_chunk = [];
        }

        continue;
    }

    $current_chunk[] = $item;
}

if (count($current_chunk) > 0) {
    $chunks[] = $current_chunk;
}

var_dump($chunks);

观看演示here。

Answer 2

array_reduce($array, function ($prev, $curr) {
if (count($prev) == 0 && $curr == 0) {
    return $prev;
}
if ($curr == 0) {
    array_push($prev, []);
    return $prev;
}
if (count($prev) == 0) {
    return array(array($curr));
}
    array_push($prev[count($prev) - 1], $curr);
    return $prev;
}, []);

如何根据某些值或索引拆分数组？

2 个答案: